mySQL - 类似子句中的变量

Question

如何在LIKE子句中使用var？

下面的代码不发送正确响应......

$query = sprintf(" 
SELECT 
place.ID AS id, 

IF(
    place.translationID IS NULL, 
    place.name, 
    placel10n.text 
    ) AS cityname, 

FROM 
places AS place 

LEFT JOIN `l10n-strings` AS placel10n ON (place.translationID = placel10n.translationID AND placel10n.languageCode = 'de') 

WHERE 
place.name LIKE CONCAT('$fchar', '%'); 
AND 
place.`status` = '1' 

"); 

Answer 1

你不喜欢这样，如果$fchar包含字符串，您要搜索：

$sql = " 
SELECT 
place.ID AS id, 

IF(
    place.translationID IS NULL, 
    place.name, 
    placel10n.text 
    ) AS cityname, 

FROM 
places AS place 

LEFT JOIN `l10n-strings` AS placel10n ON (place.translationID = placel10n.translationID AND placel10n.languageCode = 'de') 

WHERE 
place.name LIKE CONCAT('%s', '%'); 
AND 
place.`status` = '1'"; 

$query = sprintf($sql,$fchar); 

所以，如果$fchar = 'apple'，那么你的查询将会尝试匹配'apple％'。

Answer 2

想想你可以做

LIKE '$fchar%'; 

或者用事先准备好的声明中（但并不清楚你想要的sprintf的用法是什么）

place.name LIKE :fchar; 

$fchar = $fchar'.'%'; 

$something->bindParam(':fchar', $fchar, PDO::PARAM_STR);