MySQL我该如何实现这个查询？

Question

我有以下的模拟表：

+---------+-------------------+------+------+ 
| NAME | TITLE    | SIZE | Hit | 
+---------+-------------------+------+------+ 
| A  | Hippo1   | H | 0 | 
| A  | Hippo2   | H | 0 | 
| A  | Hippo3   | H | 1 | 
| A  | Hippo1   | M | 0 | 
| A  | Hippo2   | M | 1 | 
| A  | Hippo3   | M | 1 | 
| A  | Hippo1   | L | 0 | 
| A  | Hippo2   | L | 1 |  
| A  | Hippo3   | L | 1 | 
+---------+-------------------+------+------+ 
| B  | Snail1   | H | 1 | 
| B  | Snail1   | M | 0 | 
| B  | Snail1   | L | 1 | 
+---------+-------------------+------+------+ 
| C  | Dog    | H | 1 | 
| C  | Dog    | M | 0 | 
+---------+-------------------+------+------+ 
| D  | Sheep    | H | 0 | 
| D  | Sheep    | L | 1 | 
+---------+-------------------+------+------+ 
| E  | Fish    | H | 1 | 
| E  | Fish    | H | 1 | 
+---------+-------------------+------+------+ 

我要的结果将需要

+---------+----------+-------+ 
| NAME | TITLE | SCORE | 
+---------+----------+-------+ 
| A  | Hippo | 100 | 
| B  | Snail | 80 | 
| C  | Dog  | 80 | 
| D  | Sheep | 10 | 
| E  | Fish  | 100 | 
+---------+----------+-------+ 

计算比较：

• 类型最多可只有三个值：{H，M，L};
• 当所有值都存在，它们被分级为如下：H = 70，M = 20，L = 10

• ALL独特casese是

  1. 案例{H，M}：H = 80 M = 20
  2. 案例{M，L}：M = 60，L = 40
  3. 案例{H，L}：H = 90，L = 10
  4. 案例{H}：H = 100
  5. 案例{M }：M = 100
  6. Cas E {L}：L = 100
  7. 案例{H，M，L}：H = 70，M = 20，L = 10

说明：

Hippo Has case {H,M,L} 
Snail has case {H,M,L} 
Dog has case {H,M} 
Sheep has case {H,L} 
Fish has case {H} 

进一步的解释

河马：虽然并非所有的大小都有一击，但Hippo已经获得了100分，因为每个病例至少有1个已经满足了一次每题。因此HIPPO3有三个HM L satsified所以河马可以conidered发现100％的

从上面提取（行是观众逻辑结构）

| A  | Hippo1   | H | 0 | 
| A  | Hippo2   | H | 0 | 
| A  | Hippo3   | H | 1 | <--Here 
+-------------------------------------------+  
| A  | Hippo1   | M | 0 | 
| A  | Hippo2   | M | 1 | 
| A  | Hippo3   | M | 1 | <--Here 
+-------------------------------------------+ 
| A  | Hippo1   | L | 0 | 
| A  | Hippo2   | L | 1 |  
| A  | Hippo3   | L | 1 | <--Here 

Answer 1

在这里你去：

select name, sum(FinalVal) Score from (
    select distinct t.name, 
    case 
     when size = 'H' then Hval 
     when size = 'M' then Mval 
     else Lval 
    end FinalVal 
    from (
    select name, 
     case 
     when sizes = 'H,L,M' then 70 
     when sizes = 'H,M' then 80 
     when sizes = 'H,L' then 90 
     when sizes = 'H' then 100 
     else 0 
     end Hval, 
     case 
     when sizes = 'H,L,M' then 20 
     when sizes = 'H,M' then 20 
     when sizes = 'L,M' then 60 
     when sizes = 'M' then 100 
     else 0 
     end Mval, 
     case 
     when sizes = 'H,L,M' then 10 
     when sizes = 'L,M' then 40 
     when sizes = 'H,L' then 10 
     when sizes = 'L' then 100 
     else 0 
     end Lval 
    from (
     select name, group_concat(distinct size order by size) sizes from t 
     group by name 
    ) s1 
) s2 
    join t on t.name = s2.name 
    where hit 
) final 
group by name 

目前还不清楚如何根据您的数据获得标题（实际上结果是数据不存在于原始表中，例如Hippo，而不是Hippo1。但我会把它留给你。

这将导致：

+------+-------+ 
| NAME | SCORE | 
+------+-------+ 
| A | 100 | 
| B | 80 | 
| C | 80 | 
| D | 10 | 
| E | 100 | 
+------+-------+