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嘿,我的Java代码有问题。如果我在IDFiELD中输入一个文本,然后按下“Enter”,然后出现“ID不能识别,请重试......”,但它显示了我的表格中的值。那么我该如何解决这个问题。我该如何实现这个代码?
所以这是我在Java Eclipse代码:
IDField.addKeyListener(new KeyAdapter() {
public void keyPressed(KeyEvent evnt) {
if (evnt.getKeyCode() == KeyEvent.VK_ENTER) {
try {
String query = "select * from employee where IDNo = ?";
PreparedStatement pst = connection.prepareStatement(query);
pst.setString(1, IDField.getText());
ResultSet rs = pst.executeQuery();
table.setModel(DbUtils.resultSetToTableModel(rs));
int count = 0;
while (rs.next()) {
count += 1;
}
if (count == 1) {
JOptionPane.showMessageDialog(null, "ID Verified!");
IDField.setText(null);
} else {
JOptionPane.showMessageDialog(null, "ID was'nt recognize, Try again...");
}
rs.close();
pst.close();
} catch (Exception e) {
JOptionPane.showMessageDialog(null, e);
}
}
}
});
我希望你能帮助我。谢谢。
?也许不止一个'员工'具有相同的'IDNo'? –
?首先,我不添加“table.setModel(DbUtils.resultSetToTableModel(rs));”它正常工作。然后,当把这张桌子放在桌上时,我的问题就出现了。 –