我正在递归地调用一个函数,我希望它们都绘制在同一个绘图中。当我尝试创建一个处理程序,并与我得到以下错误的参数传递它:对不同的子功能使用相同的绘图
??? Error using ==> set Invalid handle object.
Error in ==> triangle at 23
set(h, 'xdata', [x1,x3], 'ydata', [y1,y3]);
叫我的功能我已经创建了一个处理程序之前,并设置我的喜好:
h = plot([0,1],[0,0]);
set(h, 'erasemode', 'none');
triangle(0,0,1,0,10,0,h)
这是我的功能:
function triangle(x1,y1,x2,y2, deepth , n,h)
%Paints a equilateral triangle for two given Points
if depth > n
shg
clf reset
%vector
v_12 = [x2-x1;y2-y1];
%rotate vector
g_uz = [0.5,-sqrt(3)/2;sqrt(3)/2, 0.5];
p = g_uz * v_12;
x3 = p(1) + x1;
y3 = p(2) + y1;
axis([-10 10 -10 10]);
axis off
drawnow
set(h, 'xdata', [x1,x3], 'ydata', [y1,y3]);
drawnow
set(h, 'xdata', [x2,x3], 'ydata', [y2,y3]);
drawnow
v_13 = [x3-x1,y3-y1];
v_23 = [x3-x2,y3-y2];
% 1-3 triangle
triangle(x1+v_13(1)/3,y1 + v_13(1)/3, x1+ 2*v_13(1)/3,y1 + 2*v_13(1)/3, tiefe, n+1);
end
您是否知道任何解决方案?我如何绘制一个对象形成我称之为的函数?