梳理查询

Question

select sum(a.perdblnc), a.actindx 
from [CASH].[dbo].[GL00100] b 
    inner join [CASH].[dbo].[GL10111] a 
on b.actindx = a.actindx 
where b.actnumbr_1 = 1020 
group by a.actindx 

Return: 
42378.15000 41 
54072.64000 42 
31698.21000 43 
75552.65000 44 

select sum(a.perdblnc), a.actindx 
from [CASH].[dbo].[GL00100] b 
    inner join [CASH].[dbo].[GL10110] a 
on b.actindx = a.actindx 
where b.actnumbr_1 = 1020 
group by a.actindx 

Retuns: 
28711.94000 41 
53781.08000 42 
26281.17000 43 
69345.59000 44 

我需要合并它，以便它返回总和或两个查询。最终的结果应该是：

57423.88 41 
107562.16 42 
52562.34 43 
138691.18 44 

Answer 1

你要总结工会...

select sum(u.t), u.actindx 
from (

select sum(a.perdblnc) as t, a.actindx 
from [CASH].[dbo].[GL00100] b 
    inner join [CASH].[dbo].[GL10111] a 
on b.actindx = a.actindx 
where b.actnumbr_1 = 1020 
group by a.actindx 

union all 

select sum(a.perdblnc), a.actindx 
from [CASH].[dbo].[GL00100] b 
    inner join [CASH].[dbo].[GL10110] a 
on b.actindx = a.actindx 
where b.actnumbr_1 = 1020 
group by a.actindx 

) u 
group by u.actindx 

的union all是必需的极少数情况下有DUPLIC在2 GL表中吃了一笔。

Answer 2

您可以使用UNION加入结果集两个（或更多）的查询：

在一个更简单的场景：

SELECT 'Anna' as Name, 18 as Age 
UNION 
SELECT 'Bob' as Name, 19 as Age 

结果：

# | NAME | AGE 
0 | Anna | 18 
1 | Bob | 19 

Answer 3

你试过类似的东西吗？ -

 
select sum(a.perdblnc) + sum(c.perdblnc), a.actindx 
from [CASH].[dbo].[GL00100] b 
    inner join [CASH].[dbo].[GL10111] a 
    inner join [CASH].[dbo].[GL10110] c 
on b.actindx = a.actindx 
where b.actnumbr_1 = 1020 
group by a.actindx 

Answer 4

既然你只总结一列，你可以使用像子查询：

select act.actindx 
,  (select sum(a.perdblnc) from [CASH].[dbo].[GL10110] a 
     where a.actindx = act.actindx) + 
     (select sum(a.perdblnc) from [CASH].[dbo].[GL10111] b 
     where b.actindx = act.actindx) 
from [CASH].[dbo].[GL00100] act 
where act.actnumbr_1 = 1020 
group by 
     act.actindx 

如果你需要更多的列时，你通常会与子查询的另一种形式去，如：

select act.actindx 
,  sub_a.total + sub_b.total 
from [CASH].[dbo].[GL00100] act 
left join 
     (
     select a.actindx 
     ,  sum(a.perdblnc) as total 
     from [CASH].[dbo].[GL10110] a 
     group by 
       a.actindx 
     ) sub_a 
on  a.actindx = act.actindx 
left join 
     (
     select b.actindx 
     ,  sum(b.perdblnc) as total 
     from [CASH].[dbo].[GL10111] b 
     group by 
       b.actindx 
     ) sub_b 
on  b.actindx = act.actindx 
where act.actnumbr_1 = 1020 
group by 
     act.actindx