删除重复的列值

Question

考虑我的表

+----+------+--------+----------+ 
| ID | Name | Salary | Month | 
+----+------+--------+----------+ 
| 1 | a | 5000 | Jan  | 
| 2 | b | 5500 | Jan  | 
| 3 | b | 5300 | Feb  | 
| 4 | b | 5300 | Mar  | 
| 5 | b | 5300 | Apr  | 
| 6 | b | 5300 | May  | 
| 7 | b | 5300 | June  | 
| 8 | b | 5300 | July  | 
+----+------+--------+----------+

我需要显示

+----+------+--------+----------+ 
| ID | Name | Salary | Month | 
+----+------+--------+----------+ 
| 1 | a | 5000 | Jan  | 
| 2 | b | 5500 | Jan  | 
| 3 |  | 5300 | Feb  | 
| 4 |  | 5300 | Mar  | 
| 5 |  | 5300 | Apr  | 
| 6 |  | 5300 | May  | 
| 7 |  | 5300 | June  | 
| 8 |  | 5300 | July  | 
+----+------+--------+----------+

能ANY1帮助

Answer 1

我假设的结果由name列进行排序（可能那么薪水？），您可以使用分析函数ROW_NUMBER来挑选第一个，并只打印出一个。 您可能要调整了一下周围的查询，但这里的主要思想：

SELECT id, CASE rn WHEN 1 THEN name ELSE null END, salary, month 
FROM  (SELECT id, name, salary, month, 
       ROW_NUMBER() OVER (PARTITION BY name ORDER BY salary) AS rn 
     FROM some_table) 
ORDER BY name, rn 

Answer 2

请尝试以下查询MS SQL SERVER：

select 
    a.ID, 
    case when a.Name=b.Name then NULL else a.Name end Name, 
    a.Salary, 
    a.[Month] 
from YourTable a left join YourTable b 
    on a.ID=b.ID+1