根据If条件在Mysql触发器中使用Select INTO语句

我想写一个触发器。触发工作在以下方式：根据If条件在Mysql触发器中使用Select INTO语句

当表R_published获取进入一个新的条目，基于列的值（R_published.whichPublishable），它需要从任一project_task_goodread_master表或project_document_master表复制到一排R_publishedGoodReads或R_publishedDocuments表分别。

我写了下面的扳机，我得到的错误：“＃1327 - 未声明的变量：R_publishedGoodReads”

CREATE TRIGGER trigger_after_published 

    AFTER INSERT ON R_published 

    FOR EACH ROW 

    BEGIN 

    IF (NEW.whichPublishable=1) THEN 

     SELECT * INTO R_publishedGoodReads FROM project_task_goodread_master 
WHERE 

goodReadID= new.publishedItemId; 

    ELSEIF (NEW.whichPublishable=2) THEN 

     SELECT * INTO R_publishedDocuments FROM project_document_master where 

documentID=new.publishedItemId; 

     END IF 

END

这有什么错的语法？我是否需要声明我用于插入的表名称？谢谢。

来源

2012-02-01 Rujuta

MySQL不支持SELECT ... INTO TABLE。见MySQL Documentation

来源

2012-02-01 04:48:59

尝试代替：

IF (NEW.whichPublishable=1) THEN 
    INSERT INTO R_publishedGoodReads (col1, col2...) 
    SELECT col1, col2... FROM project_task_goodread_master 
    WHERE goodReadID= new.publishedItemId;

来源

2012-02-01 04:51:18 Bort

CREATE TRIGGER trigger_after_published INSERT后R_published FOR EACH ROW BEGIN IF（NEW.whichPublishable = 1）THEN INSERT INTO R_publishedGoodReads SELECT * FROM project_task_goodread_master WHERE goodReadID = new.publishedItemId; ELSEIF（NEW.whichPublishable = 2）THEN INSERT INTO R_publishedDocuments SELECT * FROM project_document_master 其中 documentID = new.publishedItemId; END IF END; – Rujuta 2012-02-01 17:42:28

它仍然给我folliwing错误：＃1064 - 你的SQL语法有错误;检查与您的MySQL服务器版本相对应的手册，在第11行的''附近使用正确的语法。 – Rujuta 2012-02-01 17:43:55

不确定第11行是否正确，但尝试明确列出要插入的列名。 'INSERT INTO R_publishedGoodReads（COL1，COL2）SELECT COL1，col2'而非'INSERT INTO R_publishedGoodReads SELECT *' – Bort 2012-02-01 17:46:38

根据If条件在Mysql触发器中使用Select INTO语句

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