使用Quartz 2D解析pdf时获得文本位置

关于pdf解析的另一个问题... 只读阅读PDF参考版本1.7“5.3.1文本定位运算符”，我有点困惑。使用Quartz 2D解析pdf时获得文本位置

我写了一些代码来获得转换矩阵和初始文本位置。

 CGPDFOperatorTableSetCallback (table, "MP", &op_MP);//Define marked-content point 
    CGPDFOperatorTableSetCallback (table, "DP", &op_DP);//Define marked-content point with property list 
    CGPDFOperatorTableSetCallback (table, "BMC", &op_BMC);//Begin marked-content sequence 
    CGPDFOperatorTableSetCallback (table, "BDC", &op_BDC);//Begin marked-content sequence with property list 
    CGPDFOperatorTableSetCallback (table, "EMC", &op_EMC);//End marked-content sequence 

    //Text State operators 
    CGPDFOperatorTableSetCallback(table, "Tc", &op_Tc); 
    CGPDFOperatorTableSetCallback(table, "Tw", &op_Tw); 
    CGPDFOperatorTableSetCallback(table, "Tz", &op_Tz); 
    CGPDFOperatorTableSetCallback(table, "TL", &op_TL); 
    CGPDFOperatorTableSetCallback(table, "Tf", &op_Tf); 
    CGPDFOperatorTableSetCallback(table, "Tr", &op_Tr); 
    CGPDFOperatorTableSetCallback(table, "Ts", &op_Ts); 

    //text showing operators 
    CGPDFOperatorTableSetCallback(table, "TJ", &op_TJ); 
    CGPDFOperatorTableSetCallback(table, "Tj", &op_Tj); 
    CGPDFOperatorTableSetCallback(table, "'", &op_apostrof); 
    CGPDFOperatorTableSetCallback(table, "\"", &op_double_apostrof); 

    //text positioning operators   
    CGPDFOperatorTableSetCallback(table, "Td", &op_Td); 
    CGPDFOperatorTableSetCallback(table, "TD", &op_TD); 
    CGPDFOperatorTableSetCallback(table, "Tm", &op_Tm); 
    CGPDFOperatorTableSetCallback(table, "T*", &op_T); 

    //text object operators 
    CGPDFOperatorTableSetCallback(table, "BT", &op_BT);//Begin text object 
    CGPDFOperatorTableSetCallback(table, "ET", &op_ET);//End text object

因此，这是后应用午餐输出：

2010-09-02 15:09:23.041 testSearch[8251:207] op_BT begin 
    Integer value: 0 
    2010-09-02 15:09:23.043 testSearch[8251:207] op_BT end 
    2010-09-02 15:09:23.043 testSearch[8251:207] op_Tf begin 
    Integer value: 1 
    2010-09-02 15:09:23.044 testSearch[8251:207] op_Tf end 
    2010-09-02 15:09:23.044 testSearch[8251:207] op_Tm begin 
    Float value: 557.364197 
    2010-09-02 15:09:23.045 testSearch[8251:207] op_Tm end 
    2010-09-02 15:09:23.045 testSearch[8251:207] op_TJ begin 
    2010-09-02 15:09:23.046 testSearch[8251:207] Array string value [0]: F 
    2010-09-02 15:09:23.046 testSearch[8251:207] Array integer value [1]: 94985208 
    2010-09-02 15:09:23.047 testSearch[8251:207] Array string value [2]: r 
    2010-09-02 15:09:23.047 testSearch[8251:207] Array integer value [3]: 94985208 
    2010-09-02 15:09:23.048 testSearch[8251:207] Array string value [4]: o 
    2010-09-02 15:09:23.048 testSearch[8251:207] Array integer value [5]: 94985208 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array string value [6]: m s 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array integer value [7]: 94985208 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array string value [8]: a 
    2010-09-02 15:09:23.050 testSearch[8251:207] Array integer value [9]: 94985208 
    2010-09-02 15:09:23.050 testSearch[8251:207] Array string value [10]: m 
    2010-09-02 15:09:23.051 testSearch[8251:207] Array integer value [11]: 94985208 
    2010-09-02 15:09:23.051 testSearch[8251:207] Array string value [12]: p 
    2010-09-02 15:09:23.052 testSearch[8251:207] Array integer value [13]: 94985208 
    2010-09-02 15:09:23.053 testSearch[8251:207] Array string value [14]: l 
    2010-09-02 15:09:23.054 testSearch[8251:207] Array integer value [15]: 94985208 
    2010-09-02 15:09:23.055 testSearch[8251:207] Array string value [16]: e t 
    2010-09-02 15:09:23.055 testSearch[8251:207] Array integer value [17]: 94985208 
    2010-09-02 15:09:23.057 testSearch[8251:207] Array string value [18]: o r 
    2010-09-02 15:09:23.057 testSearch[8251:207] Array integer value [19]: 94985208 
    2010-09-02 15:09:23.058 testSearch[8251:207] Array string value [20]: e 
    2010-09-02 15:09:23.058 testSearch[8251:207] Array integer value [21]: 94985208 
    2010-09-02 15:09:23.059 testSearch[8251:207] Array string value [22]: s 
    2010-09-02 15:09:23.059 testSearch[8251:207] Array integer value [23]: 94985208 
    2010-09-02 15:09:23.060 testSearch[8251:207] Array string value [24]: u 
    2010-09-02 15:09:23.061 testSearch[8251:207] Array integer value [25]: 94985208 
    2010-09-02 15:09:23.061 testSearch[8251:207] Array string value [26]: l 
    2010-09-02 15:09:23.062 testSearch[8251:207] Array integer value [27]: 94985208 
    2010-09-02 15:09:23.062 testSearch[8251:207] Array string value [28]: t 
    2010-09-02 15:09:23.063 testSearch[8251:207] op_TJ end

如果有人熟悉文本矩阵和文本定位运营商这将是很好解释所有的那些事儿工作。

如何使用Tm（变换矩阵和其他数据）计算文本位置（或字形？）？

来源

2010-09-02 Koteg

你发现了如何使用这些运营商？谢谢！ – pt2ph8 2010-11-15 13:49:39

@科泰：嗨！你终于设法让它工作？对于Tm，我能够获得所有六个值，但现在我看不到如何将一个单词的位置排成一条线...... 我有一个想法：如果我们在Tj，只是得到字母之间的空格（每次跳转时都一样）和Tm，得到一个单词的位置。在TJ的情况下，这是非常复杂的：获得水平平移的值以减去Tm矩阵的每个部分的数组，但是搜索该数组中的单词将比Tj更复杂。

BTW，为别人的人：

for(size_t n = 0; n < CGPDFArrayGetCount(array); n += 2) 
{ 
    if(n >= CGPDFArrayGetCount(array)) 
     continue; 

    CGPDFStringRef string; 
    success = CGPDFArrayGetString(array, n, &string); 
    if(success) 
    { 
     NSString *data = (NSString *)CGPDFStringCopyTextString(string); 
     NSLog(@"array data : %@", data); 

     [searcher.currentData appendFormat:@"%@", data]; 
     [data release]; 
    } 

    CGPDFReal real; 
    success = CGPDFArrayGetNumber(array, n+1, &real); 
    if(success) 
    { 
     NSLog(@"array real : %f", real); 
    } 
}

感谢

来源

2011-01-10 16:48:33 ipodishima

使用Quartz 2D解析pdf时获得文本位置

回答

相关问题