2011-12-17 57 views
20

我是Django的新手,尝试将作者姓名传递给视图,并根据作者姓名筛选出引用对象。这里是代码:Django:int()的基数为10的无效字面积

models.py

class Author(models.Model): 
    author_name = models.CharField(max_length=50, default='unknown') 
    author_info = models.TextField(max_length=1000) 


class Quote(models.Model): 
    author = models.ForeignKey(Author) 
    quote = models.TextField(max_length=500) 
    category= models.ForeignKey(Category) 
    pub_date = models.DateTimeField('date published') 

urls.py:

url(r'^quotes/(?P<name>\w+)/$', 'quotes.views.quotesbyauthor'), 

views.py

def quotesbyauthor(request, name): 
    aquotelist = Quote.objects.filter(author__exact = name) 
    return render_to_response(quotes_by_author.html, {'aquotelist': aquotelist }) 

不过我,当我试图让得到这个错误http://127.0.0.1:8000/quotes/you/ ('你'是一个测试作者对象,已经创建)

ValueError at /quotes/you/ 

invalid literal for int() with base 10: 'you' 

Request Method:  GET 
Request URL: http://127.0.0.1:8000/quotes/you/ 
Django Version:  1.3.1 
Exception Type:  ValueError 
Exception Value:  

invalid literal for int() with base 10: 'you' 

Exception Location:  /home/qliq/djenv/lib/python2.6/site-packages/django/db/models/fields/__init__.py in get_prep_value, line 479 
Python Executable: /home/qliq/djenv/bin/python 
Python Version:  2.6.6 
Python Path:  

['/home/qliq/djenv/quoteapp', 
'/home/qliq/djenv/lib/python2.6/site-packages/distribute-0.6.10-py2.6.egg', 
'/home/qliq/djenv/lib/python2.6/site-packages/pip-0.7.2-py2.6.egg', 
'/home/qliq/djenv/lib/python2.6', 
'/home/qliq/djenv/lib/python2.6/plat-linux2', 
'/home/qliq/djenv/lib/python2.6/lib-tk', 
'/home/qliq/djenv/lib/python2.6/lib-old', 
'/home/qliq/djenv/lib/python2.6/lib-dynload', 
'/usr/lib/python2.6', 
'/usr/lib/python2.6/plat-linux2', 
'/usr/lib/python2.6/lib-tk', 
'/home/qliq/djenv/lib/python2.6/site-packages'] 

我感谢您的帮助来解决这个问题。

+0

这是一个粘贴错误,你的.html模板没有引号吗? – jdi 2011-12-17 21:41:32

+0

也请发布更完整的回溯,因为它应该告诉你错误的特定行和上下文。尝试将名称设置为缺省关键字,例如quotesbyauthor(request,name ='') – jdi 2011-12-17 21:45:58

+0

@jdi,我用更详细的错误消息更新了问题。另外,我在模板名称周围添加了引号,但它没有效果。 – qliq 2011-12-17 21:51:47

回答

27

你想搜索作者的author_name字段,而不是id。

Quote.objects.filter(author__author_name=name) 

根据您当前的搜索,author__exact,Django的预计name是作者的ID,所以给出了一个错误,因为you不是整数。

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gah我在上面评论时完全忽略了这一点。好的眼睛:-) – jdi 2011-12-17 21:49:06

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根据U-DON的回答,他确实将其属性author_name命名为过滤器需要修复 – jdi 2011-12-17 21:51:10

+0

@jdl是的,我的字段名称不正确。我现在修好了。 – Alasdair 2011-12-17 21:55:00

4
aquotelist = Quote.objects.filter(author__author_name__exact = name) 

尝试将相应的行更改为上述内容。您现在的方式是,您将author与指定名称匹配,但author可能在此处被其ID所认为,绝对不是其author_name。格式如下:

Quote.objects.filter([model]__[field]__exact = [whatever]) 
+0

谢谢,我会记得过滤器的语法以避免类似的错误。 – qliq 2011-12-17 22:06:51

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