编辑：ORA-00936：缺少表达式编辑[ORA-00933：SQL命令未正确结束]

Question

[编辑]我被告知查询中有一个子查询，所以这里是我想出了而现在给努力。[NEW CODE]

SELECT P.prodid, P.prodname, SUM(O.qtysold) AS "TOTAL SALES" 
FROM ORDERLINE O 
INNER JOIN PRODUCT P 
ON O.prodid = P.prodid 
INNER JOIN ALLOCATION A 
ON P.prodid = A.prodid 
GROUP BY P.prodid, P.prodname 
HAVING (SELECT AVG(score) AS score 
      FROM QUALITYCHECK 
      HAVING score >= 2) 
ORDER BY 3 ASC; 

[原帖] 所以，我一直在努力做这个代码的方式给我正确的结果。我认为这是如果它工作我最准确的一项：

SELECT P.prodid, P.prodname, SUM(O.qtysold) AS "TOTAL SALES" 
FROM ORDERLINE O 
INNER JOIN PRODUCT P 
ON O.prodid = P.prodid 
INNER JOIN ALLOCATION A 
ON P.prodid = A.prodid 
GROUP BY P.prodid, P.prodname 
WHERE (SELECT AVG(score) FROM QUALITYCHECK) >= 2 
ORDER BY 3 ASC; 

〜错误是线8〜

所以让我解释什么，我试图完成。我试图从Orderline表中获取销售产品的数量，但仅限于产品的质量检查得分平均值大于2的情况。我想尝试做这项工作，但是如果有其他方法可以做到这一点，欢迎所有建议。

我还有另一种方式做它，但它给了我3和15的结果而不是1和5，我会在这里把任何人都可以解决这个问题。

SELECT P.prodid, P.prodname, SUM(O.qtysold) AS "TOTAL SALES" 
FROM ORDERLINE O 
INNER JOIN PRODUCT P 
ON O.prodid = P.prodid 
INNER JOIN ALLOCATION A 
ON P.prodid = A.prodid 
INNER JOIN QUALITYCHECK Q 
ON A.prodid = Q.prodid 
GROUP BY P.prodid, P.prodname 
HAVING AVG(Q.score) >= 2 
ORDER BY 3 ASC; 

在此先感谢：d

Answer 1

Try this 

SELECT P.prodid, P.prodname, SUM(O.qtysold) AS "TOTAL SALES" 
FROM ORDERLINE O 
     INNER JOIN PRODUCT P 
     ON O.prodid = P.prodid 
     INNER JOIN ALLOCATION A 
     ON P.prodid = A.prodid 
     INNER JOIN QUALITYCHECK Q 
     ON A.prodid = Q.prodid AND AVG(Q.score) >= 2 
     GROUP BY P.prodid, P.prodname 
ORDER BY 3 ASC; 

Answer 2

你的第二个查询似乎值得追求的目标。您收到错误的总和，因为订单行连接的次数太多。

尝试在隔离产品和优质的分组：

SELECT P.prodid, P.prodname, SUM(O.qtysold) AS "TOTAL SALES" 
FROM ORDERLINE O 
INNER JOIN (
    select P.prodid, P.prodname, p.prodid 
    FROM PRODUCT P 
    INNER JOIN QUALITYCHECK Q ON p.prodid = Q.prodid 
    GROUP BY P.prodid, P.prodname, p.prodid 
    HAVING AVG(Q.score) >= 2) P ON O.prodid = P.prodid 
INNER JOIN ALLOCATION A ON P.prodid = A.prodid 
ORDER BY 3