2009-08-28 38 views
4

我希望能够在SQL Server 2005中以某种方式做的事情是使用表名作为输入来确定组成主键的所有字段。 sp_columns似乎没有这个字段。任何想法在哪里看?如何确定SQL Server中表的主键?

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? – 2009-08-28 21:08:10

回答

6

我用这一个代码生成器,我写来获取主键:

SELECT i.name AS IndexName, 
    OBJECT_NAME(ic.OBJECT_ID) AS TableName, 
    COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName, 
    c.is_identity, c.user_type_id, CAST(c.max_length AS int) AS max_length, 
    CAST(c.precision AS int) AS precision, CAST(c.scale AS int) AS scale 
FROM sys.indexes AS i 
INNER JOIN sys.index_columns AS ic 
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id 
    ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id 
WHERE i.is_primary_key = 1 AND ic.OBJECT_ID = OBJECT_ID('dbo.YourTableNameHere') 
ORDER BY OBJECT_NAME(ic.OBJECT_ID), ic.key_ordinal 
4

- ANSI SQL兼容和SQL70开始工作:

select kcu.TABLE_SCHEMA, kcu.TABLE_NAME, kcu.CONSTRAINT_NAME, tc.CONSTRAINT_TYPE, kcu.COLUMN_NAME, kcu.ORDINAL_POSITION 
    from INFORMATION_SCHEMA.TABLE_CONSTRAINTS as tc 
    join INFORMATION_SCHEMA.KEY_COLUMN_USAGE as kcu 
    on kcu.CONSTRAINT_SCHEMA = tc.CONSTRAINT_SCHEMA 
    and kcu.CONSTRAINT_NAME = tc.CONSTRAINT_NAME 
    and kcu.TABLE_SCHEMA = tc.TABLE_SCHEMA 
    and kcu.TABLE_NAME = tc.TABLE_NAME 
where tc.CONSTRAINT_TYPE in ('PRIMARY KEY', 'UNIQUE') 
order by kcu.TABLE_SCHEMA, kcu.TABLE_NAME, tc.CONSTRAINT_TYPE, kcu.CONSTRAINT_NAME, kcu.ORDINAL_POSITION; 

- SQL Server 2005的具体:

select s.name as TABLE_SCHEMA, t.name as TABLE_NAME 
    , k.name as CONSTRAINT_NAME, k.type_desc as CONSTRAINT_TYPE 
    , c.name as COLUMN_NAME, ic.key_ordinal AS ORDINAL_POSITION 
    from sys.key_constraints as k 
    join sys.tables as t 
    on t.object_id = k.parent_object_id 
    join sys.schemas as s 
    on s.schema_id = t.schema_id 
    join sys.index_columns as ic 
    on ic.object_id = t.object_id 
    and ic.index_id = k.unique_index_id 
    join sys.columns as c 
    on c.object_id = t.object_id 
    and c.column_id = ic.column_id 
order by TABLE_SCHEMA, TABLE_NAME, CONSTRAINT_TYPE, CONSTRAINT_NAME, ORDINAL_POSITION; 
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当然你会想添加一个“where”子句。 Where TABLE_NAME ='mytable' – ChickenMilkBomb 2009-08-28 21:12:40

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@Nick您可以编辑帖子而不是添加评论,也可以添加一些代码格式,因为您的查询不容易阅读 对于ANSI方法,虽然 – MattH 2009-08-28 21:23:39

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SHEEESH!学习将代码格式化为代码 - 突出显示一个部分,然后单击工具栏中的“代码”按钮(010 101) - 请! – 2009-08-28 21:28:15

2

试试这个:

SELECT * 
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE 
WHERE table_name = 'your_table_name' 
    AND constraint_name LIKE 'PK%' 
2
select * 
from information_schema.Table_Constraints 
where Table_Name = @tableName 

看到这个MSDN Listing for Table Constraints

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这不会获得主键中涉及的列名称 – MattH 2009-08-28 21:21:44

1

我通常发现...

sp_help <table> 

给了我一切,我需要知道有关表(包括索引信息)。

4

实际上,主键是不同于表上的索引。也不是聚集索引。是约束,所以要寻找它的适当位置是sys.key_constraints

select ic.key_ordinal, cl.name, ic.is_descending_key 
from sys.key_constraints c 
join sys.indexes i on c.parent_object_id = i.object_id 
    and c.unique_index_id = i.index_id 
join sys.index_columns ic on ic.object_id = i.object_id 
    and ic.index_id = i.index_id  
join sys.columns cl on cl.object_id = i.object_id 
    and ic.column_id = cl.column_id 
where c.type = 'PK' 
    and 0 = ic.is_included_column 
    and i.object_id = object_id('<tablename>') 
order by ic.key_ordinal 
0

在SQL2005这个带回一排名称的主键,然后在“的index_keys”

给出了列的列表
sp_help myTable 
0

最后我用这个...

select cu.constraint_catalog, 
     cu.constraint_schema, 
     cu.table_name, 
     cu.constraint_name, 
     constraint_type, 
     column_name, 
     ordinal_position 

from information_schema.key_column_usage cu 

     join information_schema.table_constraints as tc 
      on tc.constraint_catalog = cu.constraint_catalog and 
       tc.constraint_schema = cu.constraint_schema and 
       tc.constraint_name = cu.constraint_name and 
       tc.table_name  = cu.table_name 

where cu.table_name = 'table_name_goes_here' 

order by constraint_name, ordinal_position 
您正在使用什么版本的SQL Server