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我使用DataContractJsonSerializer将JSON字符串转换为类,但始终返回一个空对象。 我在记事本中用'JSON查看器'扩展名测试了字符串,是有效的。搜索长时间的错误并比较其他示例。DataContractJsonSerializer不工作
这是缩写形式我的JSON字符串:
{
"error":[],
"result": {
"BCH": {"aclass":"currency","altname":"BCH","decimals":10,"display_decimals":5},
"DASH": {"aclass":"currency","altname":"test"}
}
}
的类GetAssetInfoResponse和assetinfo的包含属性与数据成员属性,但属性结果(后反序列化)不包含任何物体。
[DataContract]
[KnownType(typeof(AssetInfo))]
public class GetAssetInfoResponse
{
[DataMember(Name = "error")]
public List<string> Error { get; set; }
[DataMember(Name = "result")]
public List<Dictionary<string, AssetInfo>> Result { get; set; }
}
[DataContract]
public class AssetInfo
{
/// <summary>
/// Alternate name.
/// </summary>
[DataMember(Name = "altname")]
public string Altname { get; set; }
/// <summary>
/// Asset class.
/// </summary>
[DataMember(Name = "aclass")]
public string Aclass { get; set; }
/// <summary>
/// Scaling decimal places for record keeping.
/// </summary>
[DataMember(Name = "decimals")]
public int Decimals { get; set; }
/// <summary>
/// Scaling decimal places for output display.
/// </summary>
[DataMember(Name = "display_decimals")]
public int DisplayDecimals { get; set; }
}
这是我的测试代码:
var stream = new MemoryStream(Encoding.Unicode.GetBytes(strName))
{
Position = 0
};
var serializer = new DataContractJsonSerializer(typeof(GetAssetInfoResponse));
GetAssetInfoResponse test = (GetAssetInfoResponse)serializer.ReadObject(stream);
Console.ReadLine();
我不能使用Newtonsoft.Json扩展,因为项目不应包含任何外部的依赖。 有没有另一种方法将JSON字符串转换为类?
谢谢您的时间
谢谢!现在它可以工作。 – patbec