使用GetPixel和SetPixel很容易,但速度很慢,所以我试图使用LockBits。如何使用LockBits为黄色的位图中的黑色像素以黄色着色?
我有这样的方法我也很久以前就两幅图像之间的比较:
public static Bitmap FastComparison(Bitmap bmp1,Bitmap bmp2)
{
tolerancenumeric = 15;
int tolerance = tolerancenumeric * tolerancenumeric +
tolerancenumeric * tolerancenumeric +
tolerancenumeric * tolerancenumeric; //dr * dr + dg * dg + db * db;
bmp3 = new Bitmap(512,512);
PixelFormat pxf = PixelFormat.Format24bppRgb;
Rectangle rect = new Rectangle(0, 0, bmp1.Width, bmp1.Height);
BitmapData bmpData1 = bmp1.LockBits(rect, ImageLockMode.ReadWrite, pxf);
BitmapData bmpData2 = bmp2.LockBits(rect, ImageLockMode.ReadWrite, pxf);
BitmapData bmpData3 = bmp3.LockBits(rect, ImageLockMode.ReadWrite, pxf);
IntPtr ptr1 = bmpData1.Scan0;
IntPtr ptr2 = bmpData2.Scan0;
IntPtr ptr3 = bmpData3.Scan0;
int numBytes = bmpData1.Stride * bmp1.Height;
byte[] rgbValues1 = new byte[numBytes];
Marshal.Copy(ptr1, rgbValues1, 0, numBytes);
bmp1.UnlockBits(bmpData1);
byte[] rgbValues2 = new byte[numBytes];
Marshal.Copy(ptr2, rgbValues2, 0, numBytes);
bmp2.UnlockBits(bmpData2);
for (int counter = 0; counter < rgbValues1.Length; counter += 3)
{
int dr, dg, db;
dr = (int)rgbValues2[counter] - (int)rgbValues1[counter];
dg = (int)rgbValues2[counter + 1] - (int)rgbValues1[counter + 1];
db = (int)rgbValues2[counter + 2] - (int)rgbValues1[counter + 2];
int error = dr * dr + dg * dg + db * db;
int y, x;
y = (counter/3)/512;
x = (counter - y * 512 * 3)/3;
if ((x == 479) && (y == 474))
{
Byte r1, g1, b1, r2, g2, b2;
r1 = rgbValues1[counter];
b1 = rgbValues1[counter+1];
g1 = rgbValues1[counter+2];
r2 = rgbValues2[counter];
b2 = rgbValues2[counter+1];
g2 = rgbValues2[counter+2];
}
if (error < tolerance)
{
rgbValues1[counter] = 0;
rgbValues1[counter + 1] = 0;
rgbValues1[counter + 2] = 0;
}
}
Marshal.Copy(rgbValues1, 0, ptr3, numBytes);
bmp3.UnlockBits(bmpData3);
return bmp3;
}
但现在我还需要使用LockBits但有一个图像和颜色不黑黄色的所有像素。
我开始新的方法:
public Bitmap ChangeColors(Bitmap bmp1)
{
bmpColors = new Bitmap(512, 512);
PixelFormat pxf = PixelFormat.Format24bppRgb;
Rectangle rect = new Rectangle(0, 0, bmp1.Width, bmp1.Height);
BitmapData bmpData1 = bmp1.LockBits(rect, ImageLockMode.ReadWrite, pxf);
IntPtr ptr1 = bmpData1.Scan0;
int numBytes = bmpData1.Stride * bmp1.Height;
byte[] rgbValues1 = new byte[numBytes];
Marshal.Copy(ptr1, rgbValues1, 0, numBytes);
bmp1.UnlockBits(bmpData1);
for (int counter = 0; counter < rgbValues1.Length; counter += 3)
{
int y, x;
y = (counter/3)/512;
x = (counter - y * 512 * 3)/3;
Byte r1, g1, b1;
r1 = rgbValues1[counter];
b1 = rgbValues1[counter + 1];
g1 = rgbValues1[counter + 2];
}
return bmpColors;
}
,但不知道如何使它这样的位图bmpColors将原来的一个,但与不是黑黄色的所有像素。
我很困惑。您的标题讨论了GetPixel的性能(非常糟糕),但您似乎没有在代码中使用GetPixel。 – 2014-09-22 14:34:31
更改了标题。我想要的是知道如何使用LockBits来做到这一点。为所有没有黄色的黑色像素着色。如果像素为黑色,则将其保留为黑色,否则以黄色将其着色 – 2014-09-22 14:38:09
听起来像是彩色矩阵的工作。 http://msdn.microsoft.com/en-us/library/6tf7sa87(v=vs.110).aspx – asawyer 2014-09-22 14:39:23