我试图做使用AS3 REST客户端调用REST服务时,我下面这个教程流错误:http://help.adobe.com/en_US/as3/dev/WSb2ba3b1aad8a27b061afd5d7127074bbf44-8000.html使用AS3
我的代码如下:
import flash.events.Event;
import flash.events.ErrorEvent;
import flash.events.IOErrorEvent;
import flash.events.SecurityErrorEvent;
import flash.net.URLLoader;
import flash.net.URLRequest;
import flash.net.URLRequestMethod;
import flash.net.URLVariables;
var url:String = "https://localhost:8443/restcomponent/tesimalex";
var requestor:URLLoader = new URLLoader();
function restServiceCall():void
{
trace("Calling REST Service...");
//Create the HTTP request object
var request:URLRequest = new URLRequest(url);
request.method = URLRequestMethod.GET;
//Add the URL variables
// var variables:URLVariables = new URLVariables();
// variables.method = "test.echo";
// variables.api_key = "123456ABC";
// variables.message = "Able was I, ere I saw Elba.";
// request.data = variables;
//Initiate the transaction
requestor = new URLLoader();
requestor.addEventListener(Event.COMPLETE, httpRequestComplete);
requestor.addEventListener(IOErrorEvent.IO_ERROR, httpRequestError);
requestor.addEventListener(SecurityErrorEvent.SECURITY_ERROR, httpRequestError);
requestor.load(request);
}
function httpRequestComplete(event:Event):void
{
trace(event.target.data);
}
function httpRequestError(error:ErrorEvent):void{
trace("An error occured: " + error.toString());
}
之间的唯一性差异我的代码和教程中的代码是URL变量,我评论过,以及使用的网址。
我的REST服务是一个简单的GET,如果我在浏览器中键入url,它会显示我返回的JSON。
但在我的AS3,当我打电话restServiceCall()
返回以下错误的方法:
Error opening URL ' https://localhost:8443/restcomponent/tesimalex ?' An error occured: [IOErrorEvent type="ioError" bubbles=false cancelable=false eventPhase=2 text="Error #2032: Stream Error. URL: https://localhost:8443/restcomponent/tesimalex ?"]
任何人都知道什么是错?
错误#2032通常会在Flash Player因任何原因无法访问使用的URL(URL不可用,被阻止...)时被触发,因此请尝试验证您的URL是否可访问... – akmozo