0
从去游览采取:转:Is * Var是Var的“子类”吗?
package main
import (
"fmt"
"math"
)
type Abser interface {
Abs() float64
}
func main() {
var a Abser
f := MyFloat(-math.Sqrt2)
v := Vertex{3, 4}
a = f
a = &v
// v == Vertex != *Vertex -> exception
a = v
}
type MyFloat float64
func (f MyFloat) Abs() float64 {
if f < 0 {
return float64(-f)
}
return float64(f)
}
type Vertex struct {
X, Y float64
}
func (v *Vertex) Abs() float64 {
return math.Sqrt(v.X*v.X + v.Y*v.Y)
}
然而,把func (v *Vertex) Abs() float64
为func (v Vertex) Abs() float64
时,代码编译:
package main
import (
"math"
)
type Abser interface {
Abs() float64
}
func main() {
var a Abser
f := MyFloat(-math.Sqrt2)
v := Vertex{3, 4}
a = f
// Since *Vertex != Vertex, this shouldn't compile, should it?
a = &v
a = v
}
type MyFloat float64
func (f MyFloat) Abs() float64 {
if f < 0 {
return float64(-f)
}
return float64(f)
}
type Vertex struct {
X, Y float64
}
func (v Vertex) Abs() float64 {
return math.Sqrt(v.X*v.X + v.Y*v.Y)
}
为什么在第二个例子中运行?