如何使用XPath选择

下面的兄弟标签我有一个HTML文件中像这样：如何使用XPath选择

<div id="note"> 
<a name="overview"></a> 
<h3>Overview</h3> 
<p>some text1...</p> 
<a name="description"></a> 
<h3>Description</h3> 
<p>some text2 ...</p> 
</div> 
           `

我想找回段落，每个标题。例如，overview：some text1 description：some text 2 ... 我想用python在xpath中编写这个。谢谢。

来源

2013-07-31 Gomeisa

找到所有h3标签，在它们之间迭代，并在迭代循环的每一个步骤，找到一个兄弟标签p：

import urllib2 
from lxml import etree 

URL = "http://www.kb.cert.org/vuls/id/628463" 
response = urllib2.urlopen(URL) 

parser = etree.HTMLParser() 
tree = etree.parse(response, parser) 

for header in tree.iter('h3'): 
    paragraph = header.xpath('(.//following-sibling::p)[1]') 
    if paragraph: 
     print "%s: %s" % (header.text, paragraph[0].text)

打印：

Overview: The Ruby on Rails 3.0 and 2.3 JSON parser contain a vulnerability that may result in arbitrary code execution. 
Description: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
Impact: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
Solution: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
Vendor Information : Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
CVSS Metrics : Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
References: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
Credit: Thanks to Lawrence Pit of Mirror42 for discovering the vulnerability. 
Feedback: If you have feedback, comments, or additional information about this vulnerability, please send us 
Subscribe to Updates: Receive security alerts, tips, and other updates.

来源

2013-07-31 06:39:25 alecxe

感谢您的回复。我得到这个错误： lxml.etree.XMLSyntaxError：从LXML进口etree 进口的urllib 从StringIO的进口StringIO的：打开和结束标记不匹配：链接，此行代码1和头部，1号线，列485 url ='http://www.kb.cert.org/vuls/id/628463' text = urllib.urlopen（url）.read（） f = StringIO（text） tree = etree.parse（f ） headers = tree.xpath（'// h3'） for header in header： paragraph = header.xpath（'（.// following-sibling :: p）[1]'）[0] print “％s：％s”％（header.text，paragraph.text） p.s.我是新的python和xpath。 – Gomeisa

@Golbarghajian我更新了代码，请检查。 – alecxe

它的工作，谢谢sooo多。 – Gomeisa

如何使用XPath选择

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