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我想选择在C#选择节点使用XPath
使用XPath节点这是我的XML文件
<?xml version="1.0" encoding="utf-8"?>
<xObject version="3.0.2002.0" xmlns="http://schemas.microsoft.com/wix/2006/objects">
<section id="*" type="product">
<table name="NotThis">
<row sourceLineNumber="D:\bla\bla\">
<field>Borderish.fo</field>
<field>Documents</field>
<field>1</field>
<field>No, not this line here 1</field>
</row>
<row sourceLineNumber="D:\blah\blah\">
<field>Charterish</field>
<field>Documents</field>
<field>1</field>
<field>No not, this line here 2</field>
</row>
</table>
<table name="XFile">
<row sourceLineNumber="D:\bla\bla\">
<field>Borderish.fo</field>
<field>Documents</field>
<field>1</field>
<field>This line here 1</field>
</row>
<row sourceLineNumber="D:\blah\blah\">
<field>Charterish</field>
<field>Documents</field>
<field>1</field>
<field>This line here 2</field>
</row>
</table>
</section>
</xObject>
这是我的C#代码,这似乎行不通
XmlDocument doc = new XmlDocument();
doc.Load("Testing.xml");
XmlNode root = doc.DocumentElement;
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("ns", "xmlns="http://schemas.microsoft.com/wix/2006/objects"");
XmlNodeList nodeList = root.SelectNodes("ns:table[@type='XFile']/ns:row", nsmgr);
foreach (XmlNode xn in nodeList)
{
string fieldLine = xn["Field"].InnerText;
Console.WriteLine("Field: {4}", fieldLine);
}
我想要输出的是每隔4个字段的表格名称=“xfile”,像这样:
This line here 1
This line here 2
如果您知道解决方案或更好的方法,请让我知道。