SQL - 基于另一列的开始和结束日期

Question

简化的结构。

我需要一个有4动作类型和1

动作类型的记录可能是在该州多次，我需要他们的时候

单独行的记录之间的两个日期

例如，对于IncidentId = 1

• 行1 - 开始时间= 2017年1月1日14点（ID：3） - 结束时间= 2017年1月1日20点（ID：5）
• 第2行 - StartTime = 2017-01-01 21:00（id：6） - End Time = 2017- 01-02 11:00（ID：9）

 

    CREATE TABLE #returntable 
     ( 
     [incidentid] INT, 
     [starttime] DATETIME, 
     [endtime] DATETIME 
    ) 

    CREATE TABLE #testtableofdoom 
     ( 
     [incidentlogid] INT, 
     [incidentid] INT, 
     [timestamp]  DATETIME, 
     [actiontypeid] INT 
    ) 

    INSERT INTO #testtableofdoom 
      (incidentlogid, incidentid, timestamp, actiontypeid) 
    VALUES (1, 1, '2017-01-01 09:00', 1) 
     , (2, 1, '2017-01-01 11:00', 1) 
     , (3, 1, '2017-01-01 14:00', 4) 
     , (4, 1, '2017-01-01 16:00', 4) 
     , (5, 1, '2017-01-01 20:00', 1) 
     , (6, 1, '2017-01-01 21:00', 4) 
     , (7, 1, '2017-01-02 09:00', 4) 
     , (8, 2, '2017-01-02 10:00', 1) 
     , (9, 1, '2017-01-02 11:00', 1) 
     , (10, 1, '2017-01-02 14:00', 1) 
     , (11, 2, '2017-01-02 15:00', 4) 
     , (12, 1, '2017-01-02 16:00', 1)  
     , (13, 1, '2017-01-02 17:00', 1) 
     , (14, 1, '2017-01-02 18:00', 1) 
     , (15, 2, '2017-01-02 15:00', 1); 

    DROP TABLE #testtableofdoom 

    DROP TABLE #returntable 

Answer 1

我使用表变量来代替临时表，和更短的列名比你多，但这个工程：

declare @tt TABLE ( 
    logId INT, iId INT, 
    dt DATETIME, atId INT 

INSERT @tt (logId, iId, 
    dt, atId) values 
(1, 1, '2017-01-01 09:00', 1), 
(2, 1, '2017-01-01 11:00', 1), 
(3, 1, '2017-01-01 14:00', 4), 
(4, 1, '2017-01-01 16:00', 4), 
(5, 1, '2017-01-01 20:00', 1), 
(6, 1, '2017-01-01 21:00', 4), 
(7, 1, '2017-01-02 09:00', 4), 
(8, 2, '2017-01-02 10:00', 1), 
(9, 1, '2017-01-02 11:00', 1), 
(10, 1, '2017-01-02 14:00', 1), 
(11, 2, '2017-01-02 15:00', 4), 
(12, 1, '2017-01-02 16:00', 1), 
(13, 1, '2017-01-02 17:00', 1), 
(14, 1, '2017-01-02 18:00', 1), 
(15, 2, '2017-01-02 15:00', 1) 

Select s.logId startLogid, e.logId endLogId, 
     s.iID, s.dt startTime, e.dt endTime 
from @tt s join @tt e 
    on e.logId = 
     (Select min(logId) from @tt 
     where iId = s.iID 
      and atId = 1 
      and logId > s.logId)     
where s.aTid = 4 
     and ((Select atId from @tt 
      Where logId = 
       (Select Max(logId) from @tt 
       where logId < s.LogId 
       and iId = s.iId)) = 1 
     or Not Exists 
      (Select * from @tt 
      Where logId < s.LogId 
       and iId = s.iID))  

这将产生如下：

startLogid endLogId iID startTime    endTime 
----------- ----------- ---- ---------------- ---------------- 
    3   5  1 2017-01-01 14:00 2017-01-01 20:00 
    6   9  1 2017-01-01 21:00 2017-01-02 11:00 
    11   15  2 2017-01-02 15:00 2017-01-02 15:00 

它使用自连接。 s代表动作类型4的第一条（开始）记录，e代表动作类型1的结束记录。由于logId增量，结束记录的起始记录必须比起始记录高出logId，并且它必须比起始记录高出logId具有相同iId和atId = 1

Select s.iID, s.dt startTime, e.dt endTime 
from @tt s join @tt e 
    on e.logId = 
     (Select min(logId) from @tt -- lowest log greater than start logId 
     where iId = s.iID   -- same iId 
      and atId = 1   -- with atId = 1 
      and logId > s.logId) -- greater than start logId 

最后，开始记录必须被限制到那些“4”记录之前它其或者没有其他相同事件记录或有一个“1”记录之前立即到它。

where s.aTid = 4 
     and ((Select atId from @tt   -- atId of immed prior = 1 
      Where logId = 
       (Select Max(logId) from @tt 
       where logId < s.LogId 
       and iId = s.iId)) = 1 
     or Not Exists      -- or there is no prior record 
      (Select * from @tt 
      Where logId < s.LogId 
       and iId = s.iID)) 

Answer 2

这样的事情？

select 
d.[timestamp] as StartDate, 
(select top 1 [timestamp] 
from #testTableOfDoom d2 
where d2.incidentid = 1 and d2.[timestamp] > d.[timestamp] and actiontypeid = 1 
order by d2.[timestamp] asc 
) as EndDate 
from 
    (select 
    p.[timestamp], 
    LAG(p.actiontypeid) OVER (ORDER BY incidentlogid asc) PrevValue, 
    p.actiontypeid 
    from #testTableOfDoom p 
    where p.incidentid = 1) d 
where d.actiontypeid = 4 
and d.PrevValue <> 4