如何分组并选择SQL Server中的最新数据记录？

Question

我使用SQL Server 2012的

我查询的结果是这样的：

我如何只max(tnxdate)和sum(total)记录？

像这样：

total actbucket tnxbucket 
-------------------------------- 
4  18+ 7-12 m 

我尝试这样做：

select 
    sum(id), tnxbucket, actbucket 
from 
    (select 
     *, 
     rn = row_number()over(partition by id order by tnxdate desc) from t 
    ) x 
where 
    x.rn = 1 
group by 
    tnxbucket, actbucket 

，但它给了我这样的

total actbucket tnxbucket 
------------------------------ 
3 18+ 18+ 
1 18+ 7-12 

我想tnxbucket，actbucket即与最大tnxdate

谢谢小号！

Answer 1

试试这个

SELECT t1.total, t1.tnxdate, t2.actbucket, t2.tnxbucket 
FROM (SELECT id, SUM(total) as total, MAX(tnxdate) as tnxdate 
     FROM table 
     GROUP BY id) t1 
     LEFT JOIN table t2 ON t1.id=t2.id AND t1.tnxdate = t2.tnxdate 

Answer 2

试试这个：

;WITH cte as 
(
    SELECT 
    max(tnxdate) over (partition by id) mx, 
    sum(total) over (partition by id) total, 
    actbucket, 
    tnxbucket 
    FROM t 
) 
SELECT TOP 1 
    total, 
    actbucket, 
    tnxbucket 
FROM cte 
ORDER BY 
    mx desc, 
    tnxbucket desc