解决这个谜题的SQL

我有问题要解决这个case为我改善SQL：解决这个谜题的SQL

我来了远远低于所在，但仍然没有comppleted。

SELECT 
    a.EmpID, 
    a.EarningCode, 
    c.WeekStart, 
    c.WeekEnd, 
    CAST( (substring(a.EndTime, 1, 2) + '.' + substring(a.EndTime, 4, 2)) AS decimal(4,2) ), 
    CAST( (substring(a.StartTime, 1, 2) + '.' + substring(a.StartTime, 4, 2)) AS decimal(4,2) ), 
    a.EndTime, 
    a.StartTime 
FROM TC72_EmployeeVisits a, TC72_Employees b, TC72_PayrollWeek c 
WHERE a.EmpID = b.EmpID and c.EmpID = a.EmpID and c.EmpID = b.EmpID

来源

2012-03-17 What' sUP

告诉我们1）你在做什么，2）因为这是一个公开的挑战比赛，你希望我们多多帮助你。 – RBarryYoung 2012-03-17 17:14:17

1.区分empID和Hours 2.在这种情况下，只需要一些关键字。 – 2012-03-17 17:37:33

@FullmetalBoy - 对我的解决方案有任何想法或意见？它是否适合你的比赛？ – 2012-03-18 12:38:08

在这里，你去。好玩。感谢您的挑战。

;WITH cte0 AS 
    (SELECT 'H' AS RecType, 
      e.EmpID, 
      e.EmpName, 
      w.WeekStart, 
      w.WeekEnd, 
      NULL AS EarningCode, 
      NULL AS Hours 
    FROM dbo.TC72_EmployeeVisits v 
    JOIN dbo.TC72_PayrollWeek w ON v.VisitDate BETWEEN w.WeekStart AND w.WeekEnd 
    JOIN dbo.TC72_Employees e ON v.EmpID = e.EmpID 
    GROUP BY e.EmpID, 
      e.EmpName, 
      w.WeekStart, 
      w.WeekEnd 

    UNION 

    SELECT 'D' AS RecType, 
      e.EmpID, 
      e.EmpName, 
      w.WeekStart, 
      w.WeekEnd, 
      v.EarningCode, 
      cast(SUM(DATEDIFF(MINUTE, CONVERT(datetime, v.StartTime), CONVERT(datetime, v.EndTime))) AS float)/60 AS Hours 
    FROM dbo.TC72_EmployeeVisits v 
    JOIN dbo.TC72_PayrollWeek w ON v.VisitDate BETWEEN w.WeekStart AND w.WeekEnd 
    JOIN dbo.TC72_Employees e ON v.EmpID = e.EmpID 
    GROUP BY e.EmpID, 
      e.EmpName, 
      w.WeekStart, 
      w.WeekEnd, 
      v.EarningCode), 
cte1 AS 
    (SELECT ROW_NUMBER() over (ORDER BY EmpId ASC, RecType DESC) AS seq, * 
    FROM cte0), 

cte2 AS 
    (SELECT c1.seq, 
      c1.EmpId, 
      c1.EmpName, 
      c1.WeekStart, 
      c1.WeekEnd, 
      c1.EarningCode, 
      c1.Hours 
    FROM cte1 c1 
    WHERE seq = 1 

    UNION 

    SELECT c2.seq, 
      EmpId = CASE WHEN c1.EmpId = c2.EmpId THEN NULL ELSE c2.EmpId END, 
      EmpName = CASE WHEN c1.EmpName = c2.EmpName THEN '' ELSE c2.EmpName END, 
      WeekStart = CASE WHEN c1.WeekStart = c2.WeekStart THEN NULL ELSE c2.WeekStart END, 
      WeekEnd = CASE WHEN c1.WeekEnd = c2.WeekEnd THEN NULL ELSE c2.WeekEnd END, 
      c2.EarningCode, 
      c2.Hours 
    FROM cte1 c1 
    JOIN cte1 c2 ON c1.seq = c2.seq - 1 
    WHERE c2.seq > 1) 

SELECT EmpId, 
     EmpName, 
     WeekStart, 
     WeekEnd, 
     EarningCode, 
     Hours 
FROM cte2 
ORDER BY seq

来源

2012-03-17 19:55:07

解决这个谜题的SQL

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