Python 3.X岩石剪刀Lizard Spock问题

Question

你好，我是新来编码，但我一直坚持代码很长，似乎无法找到答案这里在stackoverflow。

无论我做什么，答案都以玩家1的第一张照片胜出：玩家一胜，摇滚跳动剪刀。

player1 = input("Player One do you want Rock, Paper, Scissors, Lizard or Spock?") 
player2 = input("Player Two do you want Rock, Paper, Scissors, Lizard or Spock?") 
print(player1) 
print(player2) 

rock = 1 
paper = 2 
scissors = 3 
lizard = 4 
spock = 5 

#Tie 

if (player1 == player2): 
print("It's a tie.") 

#Player 1 wins 

elif (player1 == 1, player2 == 3): 
    print("Player One wins, Rock beats Scissors.") 
elif (player1 == 1, player2 == 4): 
    print("Player One wins, Rock beats Lizard.") 
elif (player1 == 2, player2 == 1): 
    print("Player One wins, Paper beats Rock.") 
elif (player1 == 2, player2 == 5): 
    print("Player One wins, Paper beats Spock.") 
elif (player1 == 3, player2 == 2): 
    print("Player One wins, Scissors beats Paper.") 
elif (player1 == 3, player2 == 4): 
    print("Player One wins, Scissors beats Lizard.") 
elif (player1 == 4, player2 == 2): 
    print("Player One wins, Lizard beats Paper.") 
elif (player1 == 4, player2 == 5): 
    print("Player One wins, Lizard beats Spock.") 
elif (player1 == 5, player2 == 3): 
    print("Player One wins, Spock beats Scissors.") 
elif (player1 == 5 , player2 == 1): 
    print("Player One wins, Spock beats Rock.") 

#Player 2 wins  

elif (player2 == 1, player1 == 3): 
    print("Player Two wins, Rock beats Scissors.") 
elif (player2 == 1, player1 == 4): 
    print("Player Two wins, Rock beats Lizard.") 
elif (player2 == 2, player1 == 1): 
    print("Player Two wins, Paper beats Rock.") 
elif (player2 == 2, player1 == 5): 
    print("Player Two wins, Paper beats Spock.") 
elif (player2 == 3, player1 == 2): 
    print("Player Two wins, Scissors beats Paper.") 
elif (player2 == 3, player1 == 4): 
    print("Player Two wins, Scissors beats Lizard.") 
elif (player2 == 4, player1 == 2): 
    print("Player Two wins, Lizard beats Paper.") 
elif (player2 == 4, player1 == 5): 
    print("Player Two wins, Lizard beats Spock.") 
elif (player2 == 5, player1 == 3): 
    print("Player Two wins, Spock beats Scissors.") 
elif (player2 == 5 , player1 == 1): 
    print("Player Two wins, Spock beats Rock.") 

Answer 1

您没有正确构建自己的条件。

elif (player1 == 1, player2 == 3) 

这将创建一个tuple，然后检查其是否有感实性，它总是成功，因为这tuple不为空。您需要使用逻辑运算符and：

elif player1 == 1 and player2 == 3 

这将检查这两方面的条件是否为真。对代码中的所有类似实例执行此操作。

此外，目前还不清楚你是从这里用户期待什么：

player1 = input("Player One do you want Rock, Paper, Scissors, Lizard or Spock?") 
player2 = input("Player Two do you want Rock, Paper, Scissors, Lizard or Spock?") 
print(player1) 
print(player2) 

rock = 1 
paper = 2 
scissors = 3 
lizard = 4 
spock = 5 

它看起来像假设用户输入类似Rock，然后你想到rock = 1线'Rock'转换为1。它不这样工作。这样做的最基本的方法是与另一个if..elif块，但一本字典会更好：

player1 = input("Player One do you want Rock, Paper, Scissors, Lizard or Spock?") 
player2 = input("Player Two do you want Rock, Paper, Scissors, Lizard or Spock?") 
print(player1) 
print(player2) 

d = {'Rock':1, 'Paper':2, 'Scissors':3, 'Lizard':4, 'Spock':5} 

player1 = d.get(player1) 
player2 = d.get(player2) 

Answer 2

虽然TigerHawk覆盖你的condiction，您还可以投你输入整数。

player1 = int(player1) 
player2 = int(player2) 

现在你是一个STR（你的输入）比较为int（player == 1）。这不会产生你想要的。

player1 == 1  #fails right now since it's like asking "1" == 1 which fails. 
int(player1) == 1 # passes since it's asking 1 == 1. 

此外，您的print("It's a tie.")是缩进错误。