CREATE VIEW与生存确认

Question

我试图做到这一点：

IF NOT EXISTS (
SELECT * 
FROM sys.objects 
WHERE object_id = OBJECT_ID(N'[dbo].[viewName]') 
AND type in (N'U') 
) 

CREATE VIEW [dbo].[viewName] AS 
-- Such and such 
GO 

这将引发“‘CREATE VIEW’必须是唯一的语句在批处理”的错误。

我已经尝试了here（使用BEGIN/END环绕）和here（使用GO语句，使用动态SQL）的建议，但都没有减轻错误。

Answer 1

试试这个逻辑，你的一点关闭;

IF NOT EXISTS (SELECT * FROM dbo.sysobjects WHERE object_id= object_id(N'[dbo].[ViewName]') AND OBJECTPROPERTY(object_id, N'IsView') = 1) 

我说实话，我总是放弃并重新创建，以确保您运行的是最新版本的视图，像这样;

IF EXISTS (SELECT * FROM dbo.sysobjects WHERE object_id= object_id(N'[dbo].[ViewName]') AND OBJECTPROPERTY(object_id, N'IsView') = 1) 
BEGIN 
    DROP VIEW [dbo].ViewName 
END 
GO 

CREATE VIEW ViewName 
AS 
    SELECT 

是的，所以检查您要使用动态SQL的评论;

IF NOT EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[viewName]') AND OBJECTPROPERTY(object_id, N'IsView') = 1) 
BEGIN 
DECLARE @sql nvarchar(MAX) 
--SELECT 'Do this mofo' 
SET @sql = N'CREATE VIEW [dbo].[viewName] 
      AS 
      SELECT COUNT(1) FieldName FROM sys.objects' 

EXEC sp_executesql @sql 

END 
GO 

Answer 2

这是您目前使用SQL 2016 SP1的可能性不大，但对于后人，你现在可以做

CREATE OR ALTER VIEW ... https://stackoverflow.com/a/40707436/155892

Answer 3

可能是这样的：

DECLARE @cmd NVARCHAR(MAX)=N'CREATE VIEW ....;'; 

IF EXISTS(SELECT 1 FROM INFORMATION_SCHEMA.VIEWS AS v WHERE v.TABLE_NAME='ViewName') --yes, it's TABLE_NAME! 
    SET @cmd=STUFF(@cmd,1,6,N'ALTER'); 

EXEC(@cmd);