下面显示的这个程序,程序不能打印php文件中显示的数据表。我需要你的帮助,看看我的sql和表中有什么问题。while循环php在sql tablle
$result = mysql_query("SELECT DATE_FORMAT(thedate, '%Y %M %D') AS d, count(semail) AS av FROM `ecard2008` WHERE `sflag`='1' AND `thedate`>='2000-12-12' GROUP BY `thedate`")or die(mysql_error());
echo "<table border='1'>
<tr>
<th>Date</th>
<th>Daily Volume</th>
<th>Sent</th>
<th>Pending</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['d'] . "</td>";
echo "<td>" . $row['av'] . "</td>";
echo "<td>" . $row['av'] . "</td>";
echo "<td>" . $row['av'] . "</td>";
echo "</tr>";
}
echo "</table>";
你回应并直接在phpmyadmin运行此查询? –
是的,你是否从查询中得到任何错误? – nowhere
是的,下面的答案应该使用mysql_或mysqli_。不是都 –