如何更新以前的数据列

Question

如何获取以前的记录取决于unique_id和日期？ 我想使我的表（DBO：Daily_Summary）：

ID Partner  part_no Date  Periode_Sum  Previous_Sum 
1  aa   12 2011-12-21  40    
2  aa   12 2011-12-22  30    40 
3  bb2   13 2011-12-22  20    
4  bb2   13 2011-12-23  30    20 
5       2011-12-24 
6       2011-12-25 
7  aa   12 2011-12-26  30    70 
8  bb2   13 2011-12-27  40    50 
and so on 

这“Previous_Sum”是功能更新和功能仅更新Periode_Sum的纪录。并按伙伴分组，part_no和date

我的显示查询有错误。 当我显示由伙伴，part_no和日期的前一个记录。 previous_sum的记录只显示第一个伙伴。 这里是我的查询：

SELECT ds.partner_id, ds.part_no, ds. periode_in 
     , ds.periode_out, ds.periode_date, ds.periode_sum, 
( 
    SELECT F1.periode_sum 
    FROM Daily_Summary as F1 where 
    F1.periode_sum = 
    ( 
     SELECT Max(F2.periode_sum) 
     FROM Daily_Summary as F2 where F2.periode_date < ds.periode_date 
     and F2.partner_id=ds.partner_id and F2.part_no = ds.part_no 
    ) 
) AS Prev_Value 
FROM Daily_Summary ds 
where stsrc='A' 
order by ds.partner_id, ds.periode_date 

我尝试使用申报新PARAM但不工作：

DECLARE @prev_sum INT = 0 
DECLARE @dudut INT = 2 

SELECT @prev_sum = 
(select sum(periode_sum) 
    from Daily_Summary t1 
    where t1.partner_id = ds.partner_id and t1.part_no = ds.part_no 
     and t1.periode_date < ds.periode_date --and t1.id < t.id 
) 
FROM Daily_Summary ds 
where stsrc='A' 
order by ds.partner_id, ds.periode_date 

select partner_id,part_no,model,periode_sum, 
case when @prev_sum is null then @dudut else @prev_sum end 
FROM daily_summary 
where stsrc='A' 

Answer 1

select * into #tab from (
    select 1 as id, 'aa' as partner, 12 as part_no, 
     cast('2011-12-21' as datetime) as date, 40 as periode_sum union all 
    select 2, 'aa', 12, '2011-12-22', 30 union all 
    select 3, 'bb2', 13, '2011-12-22', 20 union all 
    select 4, 'bb2', 13, '2011-12-23', 30 union all 
    select 5, null, null, '2011-12-24', null union all 
    select 6, null, null, '2011-12-25', null union all 
    select 7, 'aa', 12, '2011-12-26', 30 union all 
    select 8, 'bb2', 13, '2011-12-27', 40 
) t 


select *, (select sum(periode_sum) 
    from #tab t1 
    where t1.partner = t.partner and t1.part_no = t.part_no 
     and t1.date < t.date and t1.id < t.id 
) as previous_sum 
from #tab t 

如果每天超过一排用于对特定的（partner，part_no）被允许那么应该使用and t1.date <= t.date and t1.id < t.id而不是and t1.date < t.date and t1.id < t.id。如果id确保所有行的正确顺序（及时），则只能使用and t1.id < t.id。

结果：

id partner part_no date      periode_sum  previous_sum 
1 aa   12   2011-12-21 00:00:00.000 40    NULL 
2 aa   12   2011-12-22 00:00:00.000 30    40 
3 bb2  13   2011-12-22 00:00:00.000 20    NULL 
4 bb2  13   2011-12-23 00:00:00.000 30    20 
5 NULL  NULL  2011-12-24 00:00:00.000 NULL   NULL 
6 NULL  NULL  2011-12-25 00:00:00.000 NULL   NULL 
7 aa   12   2011-12-26 00:00:00.000 30    70 
8 bb2  13   2011-12-27 00:00:00.000 40    50