我有一个文件名为:输出的逃逸“(”和“'”到AWK -v FS参数
#!/bin/bash
outputFile=output.txt
while read line
do
stringLine=$line
echo $stringLine | awk -v FS='(include|string)' '{print $2}'
done < $outputFile
样品含量:output.txt的我通过线与下一个代码读取线.TXT是:
sometext:include('js/jquery.ui.totop.js');
sometext:include('js/jquery.mousewheel.min.js');
我想提取字符串之间 “包括( '” 和 “');” 但是当我试图逃脱 “(”“ 有:
echo $stringLine | awk -v FS="(include\(\'|string)" '{print $2}
它返回一个错误:
awk: illegal primary in regular expression (include(|string) at string)
input record number 1, file
source line number 1
你想过我怎能逃脱(和“在FS争论什么想法?
是的,它的工作完美: 'includeFile = $(回声$标线| awk的-v FS = “包括\\\( '|' \\\)” '{打印$ 2}')' 这是最后一行 – user3709081 2014-12-11 19:05:13
我想你可以像'awk -v FS =“include \\\('|'\\\)''{print $ 2}''<<<”$ stringLine“ – 2014-12-11 19:07:33