如何从字典swift3

-3

获得价值我有Dictionary这样，我得到“OutputResult”的价值，但我怎么弄“的company_id”的价值，“部门”等。如何从字典swift3

if let convertedJsonIntoDict = try JSONSerialization.jsonObject(with: data!, options: []) as? NSDictionary 


let firstNameValue = convertedJsonIntoDict["OutputResult"] as? String 
       print("OutputResult is :\(firstNameValue!)") 

{ 
OutputResult = true; 
msg =  { 
    "company_id" = 1; 
    "department_id" = 6; 
    email = "[email protected]"; 
    "employee_code" = 014; 
    "employee_id" = 131; 
    "employee_name" = "abc dsc"; 
    "have_power" = 0; 
    ip = ""; 
    "is_deleted" = 0; 
    lastactivity = ""; 
    status = 1; 
}; 
}

来源

2016-12-07 johnyDiOS

您需要使用快速原生Dictionary而不是NSDictionary，它会让您从Dictionary轻松访问。从您的回应看起来像OutputResult包含Boolean值，也是你的company_id和department_id是在另一个字典msg所以你尝试下面的东西。

if let convertedJsonIntoDict = try JSONSerialization.jsonObject(with: data!, options: []) as? [String: Any] { 
    if let msg = convertedJsonIntoDict["msg"] as? [String: Any], let company_id = msg["company_id"] as? Int, 
     let department_id = msg["department_id"] as? Int { 
      //You can same way access other details of employee, email, etc.. 
      print(company_id) 
      print(department_id) 
    } 
}

来源

2016-12-07 06:28:00

感谢您rply但错误在这行 **如果让味精= convertedJsonIntoDict [ “味精”]，让COMPANY_ID =味精[ “COMPANY_ID”]作为？ Int， let department_id = msg [“department_id”] as？ Int ** 其显示类型“任何”没有下标成员 – johnyDiOS

@johny忘记了添加'as？ [字符串：任何]'检查编辑的答案。 –

其工作我得到它，并感谢您的教学 – johnyDiOS

如何从字典swift3

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