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给予名单上有字典清单如下图所示:如何使字典从字典
targer = [
{"id":1,"search":"xyz"},
{"id":2,"children":[
{"id":3,"search":'xyz'},
{"id":4,"search":'xyz'},
{"id":5,"children":[
{"id":6,"search":'xyz'},
{"id":7,"search":'xyz'},
{"id":8,"search":'xyz'}]},
{"id":9,"search":'xyz'},
{"id":10,"search":'xyz'}]},
{"id":11},{"id":12}]
现在我要让词典列表如下图所示,从目标列表:
output = [
{'tier1': 1, 'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 3,'searchterm': 'xyz'},
{'tier1': 2,'tier2': 4,'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 5,'tier3': 6,'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 5,'tier3': 7,'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 5,'tier3': 8, 'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 9,'searchterm': 'xyz'},
{'tier1': 2, 'tier2': 10,'searchterm': 'xyz'},
{'tier1': 11, 'searchterm': 'xyz'},
{'tier1': 12, 'searchterm': 'xyz'}]
我尝试了一些步骤: 1.首先我在转变目标列表中列出如下图所示:
mylist = [
[1, 'xyz'],
[2, 3, 'xyz'],
[2, 4, 'xyz'],
[2, 5, 6, 'xyz'],
[2, 5, 7, 'xyz'],
[2, 5, 8, 'xyz'],
[2, 9, 'xyz'],
[2, 10, 'xyz'],
[11],
[12]]
2.然后我采用下面的代码上MYLIST得到输出:
for i in lis:
dic={}
length=len(i)
if length==2:
dic['tier1']=i[0]
dic['searchterm']=i[1]
if length==3:
dic['tier1']=i[0]
dic['tier2']=i[1]
dic['searchterm']=i[2]
if length==4:
dic['tier1']=i[0]
dic['tier2']=i[1]
dic['tier3']=i[2]
dic['searchterm']=i[3]
if length==5:
dic['tier1']=i[0]
dic['tier2']=i[1]
dic['tier3']=i[2]
dic['tier4']=i[3]
dic['searchterm']=i[4]
if length==6:
dic['tier1']=i[0]
dic['tier2']=i[1]
dic['tier3']=i[2]
dic['tier4']=i[3]
dic['tier5']=i[4]
dic['searchterm']=i[5]
target.append(dic)
但我想从出应用上面的步骤直接目标列表输出。 请帮忙解决这个问题。
提示:尝试递归 – 2013-03-18 06:49:58
为什么是'等级1的'searchterm'值:11'和'等级1:12' “XYZ”?在原始数据结构中,这些字典没有“搜索”键。 – 2013-03-18 21:05:17