将两个查询合并为一个

Question

我正在从多个表中提取数据。 并试图solve this

最后我得到两个查询

1），其获取用户信息的培训相关的数据。

2）获取所有评论及其细节。

我想在一个查询中组合这两个查询。

查询1）

SELECT user_messages.messageid,user_messages.message, 
user_messages.sentby,user_messages.visibility, 

GROUP_CONCAT(post_images.image_id SEPARATOR ';') 
AS `POST_IMG_ID`, 


GROUP_CONCAT(post_images.small_pic_path SEPARATOR ';') 
AS 'POST_IMG_PATH', 

(
    SELECT count(*) FROM likes 
    WHERE element_id=user_messages.messageid 
)AS 'TOTAL_LIKES', 

smsusers.fname as 'SENTBY_FNAME', 
smsusers.lname as 'SENTBY_LNAME', 
profile_pic.small_pic_path as 'SENTBY_SMALL_PIC_PATH' 

FROM user_messages 
     INNER JOIN smsusers ON 
     user_messages.SENTBY = smsusers.id 
INNER JOIN profile_pic ON 
user_messages.SENTBY = profile_pic.userid 
left outer JOIN post_images ON 
user_messages.messageid=post_images.messageid 
WHERE user_messages.userid='1' 
GROUP BY user_messages.messageid 
order by user_messages.adddate 

其工作环节Sql Fiddle

查询2）

SELECT comments.comment_id, comments.comment, comments.comment_date, 
smsusers.fname ,smsusers.lname,profile_pic.small_pic_path 
FROM comments, smsusers , profile_pic , user_messages 
WHERE user_messages.messageid = 'm1' 
AND user_messages.userid = smsusers.id 
AND smsusers.id = profile_pic.userid 
ORDER BY comment_date 
LIMIT 0, 10; 

工作环节Sql Fiddle

Answer 1

使用的部份查询和删除相关子查询

SELECT user_messages.messageid, 
     user_messages.message, 
     user_messages.sentby, 
     user_messages.visibility, 
     GROUP_CONCAT(post_images.image_id SEPARATOR ';') AS `POST_IMG_ID`, 
     GROUP_CONCAT(post_images.small_pic_path SEPARATOR ';') AS 'POST_IMG_PATH', 
     likes.TCount AS 'TOTAL_LIKES', 
     smsusers.fname AS 'SENTBY_FNAME', 
     smsusers.lname AS 'SENTBY_LNAME', 
     profile_pic.small_pic_path AS 'SENTBY_SMALL_PIC_PATH', 
     GROUP_CONCAT(comments.comment) AS `Comments` 
FROM user_messages 
INNER JOIN smsusers ON user_messages.SENTBY = smsusers.id 
INNER JOIN profile_pic ON user_messages.SENTBY = profile_pic.userid 
LEFT OUTER JOIN post_images ON user_messages.messageid = post_images.messageid 
LEFT JOIN 
    (SELECT element_id, 
      COUNT(*) AS `TCount` 
    FROM likes 
    GROUP BY element_id) AS likes ON likes.element_id = user_messages.messageid 
LEFT JOIN comments ON comments.comment_on = user_messages.messageid 
WHERE user_messages.userid = '1' 
GROUP BY user_messages.messageid 
ORDER BY user_messages.adddate; 

Fiddle Demo