ORA-00979：不是GROUP BY表达式错误

我的问题是，我必须显示雇员的姓名和他们工作的会议数量。如果员工没有直接在任何会议上工作，则必须为该员工显示0。与此查询相关的表是：

Employee_C表：

EID NAME SALARY   MID 
--- -------------------- ----- 
e01 Wilson 53000 
e02 Smith  48000  e01 
e03 Jones  38000  e01 
e04 Loftus  41000 
e05 Fox  54000  e04 
e06 Smith  45000  e04 
e07 Green  48000 
e08 Fox   49000  e04 
e09 Wolf  41000  e04 
e10 Wang  32000  e01 
e11 Phillips 33000  e07 
e12 Liu   27000  e07

Deals_C表：

EID CONFID 
--- ------ 
e02 c00001 
e03 c00001 
e05 c00001 
e06 c00001 
e03 c00002 
e08 c00002 
e09 c00002 
e10 c00002 
e03 c00003 
e05 c00003 
e06 c00004 
e08 c00005 
e09 c00005 
e10 c00005 
e06 c00005 
e11 c00006 
e12 c00006 
e05 c00007 
e06 c00007 
e08 c00007 
e09 c00008 
e10 c00008 
e11 c00008 
e02 c00009 
e12 c00009 
e10 c00010 
e02 c00011 
e03 c00011 
e05 c00011 
e12 c00012 
e06 c00012

，我有SQL语句是

select E.Name, D.ConfID as "Number of Conferences" 
    from Employee_C E left outer join Deals_C D on E.eid = D.eid group by E.eid;

错误：

1号线选择E.Name，D.ConfID作为 * 错误 “的会议数”： ORA-00979：不是GROUP BY表达式

请帮帮忙！谢谢

来源

2013-03-26 Navy

您错过了一个聚合函数，并且您在SELECT列表中的列上没有使用GROUP BY。你需要GROUP BY E.Name因为该列是在选择：

select E.Name, count(D.ConfID) as "Number of Conferences" 
from Employee_C E 
left outer join Deals_C D 
    on E.eid = D.eid 
group by E.Name;

见SQL Fiddle with Demo

来源

2013-03-26 18:16:04 Taryn

太感谢你了！ – Navy 2013-03-26 18:39:15

ORA-00979：不是GROUP BY表达式错误

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