JavaScript匹配一个数组的片段并返回索引值

我想改变我的功能，我可以在那里搜索数组，尝试匹配数组项的任何部分并返回它的索引值，此刻它必须匹配整个searchTerm。JavaScript匹配一个数组的片段并返回索引值

 function arrayObjectIndexOf(myArray, searchTerm, property) { 
      for (var i = 0, len = myArray.length; i < len; i++) { 
       if (myArray[i][property] === searchTerm) return i; 
      } 
      return -1; 
     } 
     $scope.input.icon = "https://mapbuildr.com/assets/img/markers/solid-pin-blue.png"; 
     var look = arrayObjectIndexOf($scope.icons, $scope.input.icon, 'imageSrc');

以下是我的图标示例数组。

 $scope.icons = [ 
      {text: 'Black Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-black.png' }, 
      {text: 'Blue Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-blue.png' }, 
      {text: 'Green Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-green.png' }, 
      {text: 'Purple Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-purple.png' }, 
      {text: 'Red Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-red.png' }, 
      {text: 'Yellow Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-yellow.png' }, 
      {text: 'Orange Solid', imageSrc: 'https://mapbuildr.com/assets/img/markers/solid-pin-orange.png' } 
     ];

这就是我想在我的$scope.icons阵列，以匹配其将返回索引值

 $scope.pin = "/assets/img/markers/solid-pin-red.png";

来源

2014-09-18 ngplayground

'如果（！myarray的[I] [属性] .indexOf（SEARCHTERM）= -1）回报我;' – juvian 2014-09-18 21:28:01

你只需要使用JavaScript .search()方法。

这将搜索您的字符串，如果找不到相等的子字符串将返回-1。所以，你的比较应该是这样的：

if (myArray[i][property].search(searchTerm) !== -1) 
    return i;

下面是的jsfiddle来说明：http://jsfiddle.net/vxcjw45d/7/

来源

2014-09-18 21:29:13

JavaScript匹配一个数组的片段并返回索引值

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