2012-07-09 98 views
-1

这是我当前的代码。我想检查两个值(行)来检查文件中的匹配项。匹配索引值

def checkOS(): 
    fid1 = open("C:/Python/NSRLOS.txt", 'r') 
    fid2 = open("C:/Python/sha_sub_hashes.out", 'r') 
    outdata = open("osMatches.txt", 'w') 
    line1 = fid1.readline() 
    line2 = fid2.readline() 
    while(line1 and line2): 
     xline= line1.split(',')[1] 
     yline = line2.split("|")[3] 
     zline = xline.replace('"','') 
     if (yline == zline): 
      outdata.append([yline , zline]) 
      print xline, zline 

if __name__=="__main__": 
    checkOS() 

唯一的问题是我不知道我写那有什么,if语句之前,所有的代码只是重新格式化,以便能够从该行的指数拉。我想知道的是,如果我使用的陈述在这个意义上是有效的并且是有效的?然后我想输出相等的值。 下面是在文件中的某些行:

file2: 
"10","Amstrad 6128","Unknown","1006" 
"100","Macintosh 9.0","8.5.1","67" 
"101","Macintosh 9.0.4","na","67" 
"102","Macintosh 9.1","9.1","67" 
"103","Macintosh 9.2","9.2","67" 
"104","Macintosh 9.2.2","9.2.2","67" 
"105","Macintosh 9.x","9.X","67" 
"106","Macintosh X","10","67" 
"107","Macintosh7.5.3","7.5.3","67" 
"108","NetWare","n/a","674" 
"109","Novel Dos 7.0","7","609" 
"11","Apple II+","Unknown","67" 
"110","OS/2","Unknown","427" 



file2: 

    DD84270022E57F1850C8454FA432ADFF99588157B|index.docbook|2225|Redhat 7.3 (32bit)|Linux 

D84270022E57F1850C8464F5432ADFF99588157B|index.docbook|2225|Redhat 8.0 (32bit)|Linux 

26EEEB25D7005F9FF9EE05A8084C77242702FBAD|Localizable.strings|2142|Mac OS X 10.4|OSX 

34DC3D728C34E32F090307F575254D57E53C53FF|SYSTEM|10747904|Windows 7 Home Premium (32bit)|Windows 

279E5A766C88EEA5AB946A0AF8D0C4FC366B2AF9|totem.devhelp|21324|Linux Ubuntu Desktop 9.10 (32bit)|Linux 

279E5A766C88EEA5AB964A0AF8D0C4FC366B2AF9|totem.devhelp|21324|Linux Ubuntu Desktop 9.10 (64bit)|Linux 

B3D11390AB8683BBE443A415EDD91BFDFD482134|dslconfig.pyc|6246|Redhat 9.0 (32bit)|Linux 

现在,你可能不会发现这几行任何直接的比赛,但我知道,下了线的地方就会有至少一个比赛,因为我看到了同时浏览文件。

+0

你能给出一个来自每个文件的样本行,应该被认为是等效的或不等效的吗? – mVChr 2012-07-09 17:14:48

+3

你有一个无限循环。 – mgilson 2012-07-09 17:17:04

+1

而代码会在if中产生'AttributeError'。 – 2012-07-09 17:19:30

回答

1

你可能寻找的是这样的:

使用with()它会自动关闭该文件为您服务。

def checkOS(): 
    with open("C:/Python/NSRLOS.txt") as fid1,open("C:/Python/sha_sub_hashes.out") as fid2,open("osMatches.txt", 'w') as outdata: 
     for xline,yline in zip(fid1,fid2): #zip fetches lines from both files one by one           
      xline= xline.split(',')[1]  #use itertools.izip instead of zip if you're on python 2.x 
      yline = yline.split("|")[3] 
      zline = xline.replace('"','') 
      if yline == zline:     
       outdata.write("{0}{1}\n".format(yline , zline)) #use write to write the data back 

if __name__=="__main__": 
checkOS() 
+0

如果使用python 2.x,请考虑使用'itertools.izip'来防止将这两个文件读入内存。 – mgilson 2012-07-09 17:22:18