SQL计数不同行

具有下表。SQL计数不同行

Date Direction Market Time 
    10/17/2016 SB GRUJFK 22:05:00 
    10/18/2016 SB GRUJFK 22:05:00 
    10/19/2016 SB GRUJFK 22:05:00 
    10/20/2016 SB GRUJFK 22:05:00 
    10/21/2016 SB GRUJFK 22:05:00 
    10/23/2016 SB GRUJFK 23:20:00 
    10/23/2016 SB GRUJFK 22:30:00 
    10/24/2016 SB GRUJFK 22:30:00 
    10/25/2016 SB GRUJFK 22:30:00 
    10/26/2016 SB GRUJFK 22:30:00 
    10/27/2016 SB GRUJFK 22:30:00 
    10/28/2016 SB GRUJFK 22:30:00

我想计数不同行中的不同列数，但顺序地分配给重复行（从1..N）

Date Direction Market Time Count 
10/17/2016 SB GRUJFK 22:05:00 1 
10/18/2016 SB GRUJFK 22:05:00 1 
10/19/2016 SB GRUJFK 22:05:00 1 
10/20/2016 SB GRUJFK 22:05:00 1 
10/21/2016 SB GRUJFK 22:05:00 1 
10/23/2016 SB GRUJFK 23:20:00 1 
10/23/2016 SB GRUJFK 22:30:00 2 
10/23/2016 SB GRUJFK 23:30:00 3 
10/25/2016 SB GRUJFK 22:30:00 1 
10/26/2016 SB GRUJFK 22:30:00 1 
10/27/2016 SB GRUJFK 22:30:00 1 
10/28/2016 SB GRUJFK 22:30:00 1

因此，在这种情况下，只有10/23/2016有3个不同的值。因此，分配1中第一次出现，2到第二等

我尝试以下

select 
     departureDate, 
DIRECTION, LEG, SCHD_LEG_DEP_TM, count(SCHD_LEG_DEP_TM) over (partition by departureDate) 
from table3mirs mirs 
     INNER JOIN sys_calendar.calendar 
     ON calendar_date = mirs.departureDate 

where leg='GRUJFK' 
group by 1,2,3,4

，但得到

Date Direction Market Time Count 
10/17/2016 SB GRUJFK 22:05:00 1 
10/18/2016 SB GRUJFK 22:05:00 1 
10/19/2016 SB GRUJFK 22:05:00 1 
10/20/2016 SB GRUJFK 22:05:00 1 
10/21/2016 SB GRUJFK 22:05:00 1 
10/23/2016 SB GRUJFK 23:20:00 3 
10/23/2016 SB GRUJFK 22:30:00 3 
10/23/2016 SB GRUJFK 23:30:00 3 
10/25/2016 SB GRUJFK 22:30:00 1 
10/26/2016 SB GRUJFK 22:30:00 1 
10/27/2016 SB GRUJFK 22:30:00 1 
10/28/2016 SB GRUJFK 22:30:00 1

任何想法？谢谢你的帮助！

来源

2016-08-04 Carlos

如果你正在使用MSSQL（我想你可能会得到分区），你可以试试这个。

select 
     departureDate, 
DIRECTION, LEG, SCHD_LEG_DEP_TM, count(DISTINCT SCHD_LEG_DEP_TM) over (partition by departureDate) 
from table3mirs mirs 
     INNER JOIN sys_calendar.calendar 
     ON calendar_date = mirs.departureDate 

where leg='GRUJFK' 
group by 1,2,3,4

来源

2016-08-04 22:30:25

AFAIK你不能使用次数在一个窗口函数不同。 http://dba.stackexchange.com/questions/89031/using-distinct-in-window-function-with-over – vercelli

看起来你只是需要ROW_NUMBER ..

SELECT departureDate , 
     DIRECTION , 
     LEG , 
     SCHD_LEG_DEP_TM , 
     ROW_NUMBER() OVER (PARTITION BY departureDate ORDER BY SCHD_LEG_DEP_TM) 
FROM table3mirs mirs 
     INNER JOIN sys_calendar.calendar ON calendar_date = mirs.departureDate 
WHERE leg = 'GRUJFK' 
GROUP BY 1 , 
     2 , 
     3 , 
     4

来源

2016-08-04 23:00:52 JamieD77

SQL计数不同行

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