C我需要使用malloc和一个动态分配的数组，但是我需要打印用户输入

Question

非常多。我需要向用户询问元素的数量，然后询问他们想要的整数，最后打印出所有整数。

这是我到目前为止的代码：

int main(void) 
{ 
    int user_input = 0, elements = 0; 
    printf("How many int elements will you enter?\n"); 
    scanf("%d", &elements); 

    int* dynamic_array = (int *)malloc(sizeof(double)* elements); 

    for (int i = 0; i < elements; i++) 
    { 
    printf("Element %d?\n", i + 1); 
    scanf("%d", &dynamic_array[i], i + 1); 
    } 

    for (int printf_number = 1; printf_number <= elements; printf_number++) 
    { 
    printf("Element %d: %d\n", printf_number, (dynamic_array[user_input])); 
    } 

    free(dynamic_array); 
    dynamic_array = 0; 
    return 0; 
} 

Answer 1

问题1：你是分配sizeof(double)存储INT
问题2：你是不是遍历数组打印数字

int main(void) 
{ 
    int user_input = 0, elements = 0; 
    printf("How many int elements will you enter?\n"); 
    scanf("%d", &elements); 

    int* dynamic_array = (int *)malloc(sizeof(int)* elements); 
    if(dynamic_array == NULL) { 
    perror(" Out of memory "); 
    return 0; 
    } 

    for (int i = 0; i < elements; i++) 
    { 
    printf("Element %d?\n", i + 1); 
    scanf("%d", &dynamic_array[i]); 
    } 

    for (int printf_number = 0; printf_number < elements; printf_number++) 
    { 
    printf("Element %d: %d\n", printf_number+1, dynamic_array[printf_number]); 
    } 

    free(dynamic_array); 
    dynamic_array = 0; 
    return 0; 
} 

Answer 2

for (int printf_number = 1; printf_number <= elements; printf_number++) 
{ 
    printf("Element %d: %d\n", printf_number, (dynamic_array[user_input])); 
} 

您的索引printf_number应该从零开始，条件必须是printf_number < elements。您必须使用printf_number来索引阵列，而不是user_input。请注意0​​未初始化。

为什么在只读取int时分配一个数组与sizeof(double)？