0
根据我的计算，池化输出应该5x4x4（5个大小为4x4的特征地图），如此扁平化将产生1x80的向量。因此fc3的重量应该是20x80，但pycaffe显示的是20x125的重量。这里是prototext文件。这里是我的计算完全连接的图层称为fc3如何有20x125的权重
方程式用途（dimension_size - 内核）/步幅+ 1
CONV 1：1x5x26x26
池1：1x5x12x12
CONV 2：1x5x10x10
POOL2：1x5x4x4
input: "data"
input_shape {
dim: 1
dim: 1
dim: 28
dim: 28
}
layer {
name: "conv1"
type: "Convolution"
bottom: "data"
top: "conv1"
param {
lr_mult: 1.0
decay_mult: 1.0
}
param {
lr_mult: 2.0
decay_mult: 0.0
}
convolution_param {
num_output: 5
kernel_size: 3
stride: 1
weight_filler {
type: "gaussian"
std: 0.01
}
bias_filler {
type: "constant"
value: 0.0
}
}
}
layer {
name: "relu1"
type: "ReLU"
bottom: "conv1"
top: "conv1"
}
layer {
name: "pool1"
type: "Pooling"
bottom: "conv1"
top: "pool1"
pooling_param {
pool: MAX
kernel_size: 3
stride: 2
}
}
layer {
name: "conv2"
type: "Convolution"
bottom: "pool1"
top: "conv2"
param {
lr_mult: 1.0
decay_mult: 1.0
}
param {
lr_mult: 2.0
decay_mult: 0.0
}
convolution_param {
num_output: 5
kernel_size: 3
stride: 1
weight_filler {
type: "gaussian"
std: 0.01
}
bias_filler {
type: "constant"
value: 0.1
}
}
}
layer {
name: "relu2"
type: "ReLU"
bottom: "conv2"
top: "conv2"
}
layer {
name: "pool2"
type: "Pooling"
bottom: "conv2"
top: "pool2"
pooling_param {
pool: MAX
kernel_size: 3
stride: 2
}
}
layer {
name: "fc3"
type: "InnerProduct"
bottom: "pool2"
top: "fc3"
param {
lr_mult: 1.0
decay_mult: 1.0
}
param {
lr_mult: 2.0
decay_mult: 0.0
}
inner_product_param {
num_output: 20
weight_filler {
type: "gaussian"
std: 0.005
}
bias_filler {
type: "constant"
value: 0.1
}
}
}
layer {
name: "relu3"
type: "ReLU"
bottom: "fc3"
top: "fc3"
}
layer {
name: "drop3"
type: "Dropout"
bottom: "fc3"
top: "fc3"
dropout_param {
dropout_ratio: 0.5
}
}
layer {
name: "fc4"
type: "InnerProduct"
bottom: "fc3"
top: "fc4"
param {
lr_mult: 1.0
decay_mult: 1.0
}
param {
lr_mult: 2.0
decay_mult: 0.0
}
inner_product_param {
num_output: 10
weight_filler {
type: "gaussian"
std: 0.01
}
bias_filler {
type: "constant"
value: 0.0
}
}
}
layer {
name: "softmax"
type: "Softmax"
bottom: "fc4"
top: "softmax"
}