谷歌登录按钮按检测ios

我在他们的登录按钮上的谷歌文档挣扎。基本上，我想在按下谷歌登录按钮后立即在屏幕上添加一个活动指示器。然而，只有两个是真的会从文档下文称为谷歌登录按钮按检测ios

https://developers.google.com/identity/sign-in/ios/api/protocol_g_i_d_sign_in_u_i_delegate-p#a3674af917a79f4b87a58f3f8ff4d4002

- signInWillDispatch:error:

功能登录流程完成选择如何进行，以及用户界面应该不再显示一个微调框或其他“请稍等”的元素。更多...
- signIn:didSignInForUser:withError:

的登录流程已经完成，并已成功如果错误是零。更多...`

我不知道在哪里我可以把我的beginActivityIndicator代码，我不知道什么函数被调用后，我立刻按谷歌登录按钮。

感谢，

代码为--update - 下面是我在我的loginVC从GIDSignInUIDelegate和GIDSignInDelegate继承四大功能。几乎我需要在SignInWillDispatch之前访问函数，以便启动活动指示器。但是，我无法找到它在文档中的位置。我尝试在Google按钮上添加轻触手势识别器。当我这样做时，登录功能完全停止工作，就好像它只是一个空白UIView

// Google login buttob 
    GIDSignIn.sharedInstance().uiDelegate = self 
    GIDSignIn.sharedInstance().delegate = self 


    // Uncomment to automatically sign in the user. 
    //GIDSignIn.sharedInstance().signInSilently() 

    // TODO(developer) Configure the sign-in button look/feel 
    let googleSignInBtn = GIDSignInButton() 
    googleSignInBtn.frame.size = loginButton.frame.size 
    googleSignInBtn.center.x = loginButton.center.x 
    googleSignInBtn.center.y = loginButton.center.y + 80 
    googleSignInBtn.style = .Wide 
    self.view.addSubview(googleSignInBtn) 



func signIn(signIn: GIDSignIn!, presentViewController viewController: UIViewController!) { 
    print("Signed in with google") 
} 

func signInWillDispatch(signIn: GIDSignIn!, error: NSError!) { 
    print("Signin Will Dispatch") 
} 

func signIn(signIn: GIDSignIn!, dismissViewController viewController: UIViewController!) { 
    print("GoogleSignInDismiss") 
} 

func signIn(signIn: GIDSignIn!, didSignInForUser user: GIDGoogleUser!, withError error: NSError!) { 

    activityIndicatorBegin() // Having the activity indicator start here is too late. I need it to start as soon as the google button is pressed. Otherwise there would be a moment just after the google view dismisses without activity indicator 

    if let error = error { 
     print(error.localizedDescription) 
     return 
    } 

    let authentication = user.authentication 
    let credential = FIRGoogleAuthProvider.credentialWithIDToken(authentication.idToken, accessToken: authentication.accessToken) 

    FIRAuth.auth()?.signInWithCredential(credential) { (user, error) in 
     if let error = error { 
      self.showErrorAlert("Error Sign in Firebase with google", message: error.localizedDescription) 
     } else { 

     } 
     self.activityIndicatorEnd() 
    } 
} 

func signIn(signIn: GIDSignIn!, didDisconnectWithUser user:GIDGoogleUser!, withError error: NSError!) { 
    // Perform any operations when the user disconnects from app here. 
    print("didDisconnectWithUser") 
}

来源

2016-07-25 user172902

发布您的代码... –

不知道IOS多，但一定要检查该“指南”：https://developers.google .com /身份/登录/ ios /开始 - 整合和这一个：https://developers.google.com/identity/sign-in/ios/sign-in –

代码张贴上尉。我确实通过了开发人员指导，这里是我卡住的地方。干杯 – user172902

问题解决了。通过像上面那样编程式地创建按钮，我无法解决它。我所做的就是创建一个UIButton和根本就以下

@IBAction func signInWithGoogleBtn(sender: AnyObject) { 
    activityIndicatorBegin() 
    GIDSignIn.sharedInstance().signIn() 
}

来源

2016-07-26 01:15:54 user172902

谷歌登录按钮按检测ios

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