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我想创建一个简单的登录基于Zentask示例 - zentask - playframework,但是当我单击登录按钮调用Application.authenticate操作时,它给运行时异常。我已经标有行 - 错误Playframework:[RuntimeException:java.lang.reflect.InvocationTargetException]
[RuntimeException: java.lang.reflect.InvocationTargetException]
Application.java
public class Application extends Controller {
.........
public static class Login
{
public String email;
public String password;
public String validate()
{
if (User.authenticate(email, password) == null) {
return "Invalid user or password";
}
return null;
}
}
public static Result authenticate()
{
Form<Login> loginForm = form(Login.class).bindFromRequest(); //--- error
if(loginForm.hasErrors()) {
return badRequest(login.render(loginForm));
} else {
session("email", loginForm.get().email);
return redirect(
routes.Application.index()
);
}
}
}
我理解它是与在登录级的验证功能,因为当我删除调用用户。在验证函数中验证它的工作原理没有错误。但我无法弄清楚。
用户类是作为 -
@Entity
public class User extends Model
{
@Id
@Constraints.Required
@Formats.NonEmpty
public String userId;
@OneToOne(cascade=CascadeType.PERSIST)
AccountDetails accDetails;
public static Model.Finder<String,User> find = new Model.Finder<String,User>(String.class, User.class);
// Authenticate the user details
public static User authenticate(String email, String password)
{
String tempId = AccountDetails.authenticate(email, password).userId;
return find.ref(tempId);
}
.. . . . . . .
}
和AccountDetails类 -
@Entity
public class AccountDetails extends Model
{
@Id
String userId;
@Constraints.Required
String emailId;
@Constraints.Required
String password;
public static Model.Finder<String,AccountDetails> find =
new Model.Finder<String,AccountDetails>(String.class, AccountDetails.class);
public static AccountDetails authenticate(String email, String password)
{
return find.where()
.eq("email", email)
.eq("password", password)
.findUnique();
}
}
任何帮助,将不胜感激。
非常感谢。
没有导入声明,没有异常堆栈跟踪,碎片代码。除了你已经处理了这样的问题之外,回答这个问题是相当顽固的。 –