我有这样的例子:如何使用Java将32位尾数(IEEE754)转换为十进制数?
,并希望将其转换为十进制数。
到目前为止,我已经有代码来获取指数部分:
String[]hex={"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
String[]binary={"0000","0001","0010","0011","0100","0101","0110","0111","1000","1001","1010","1011","1100","1101","1110","1111"};
String userInput="429E0000";
String result="";
for(int i=0;i<userInput.length();i++)
{
char temp=userInput.charAt(i);
String temp2=""+temp+"";
for(int j=0;j<hex.length;j++)
{
if(temp2.equalsIgnoreCase(hex[j]))
{
result=result+binary[j];
}
}
}
System.out.println(result);
int exponent = Integer.parseInt(result.substring(1,9),2)-127;
System.out.println(exponent);
是否有Java的任何内置的命令?