使用阵列

Question

我有公司名称的数组插入多个MySQL记录，我插入每个公司名称作为单独record.below是代码

<input type="text" name="company_name[]"> 

$company_name = $_POST['company_name']; 

if($company_name) 
{ 
    foreach($company_name as $company) 
    { 
    $mycompany[] = $company; 
    } 
} 

$val="('".implode("'), ('",$mycompany)."')"; 
$sql = "INSERT INTO `table` 
(`company_name`) VALUES ".$val.""; 

上面的查询看起来像这样，它成功地插入2个记录在表。

INSERT INTO `table` (`company_name`) VALUES ('DELL'), ('IBM') 

现在的问题是，每COMPANY_NAME有一个company_code，我想每个记录插入和有第三值可以假设order_num这也是我想插入但order_num应该在所有记录相同，我需要以下

INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','DELL','axc89'), ('123','IBM','bxc90') 

Answer 1

好吧，你最后努力生产出可以理解的

1）本该代码是绝对没用：

$company_name = $_POST['company_name']; 

if($company_name) 
{ 
    foreach($company_name as $company) 
    { 
    $mycompany[] = $company; 
    } 
} 

为$ myCompany的是一个确切的$ COMPANY_NAME

重复2）为了得到你的“非常复杂”的查询

foreach($_POST['company_name'] as $key => $value) 
{ 
    $name = mysql_real_escape_string($value); 
    $code = mysql_real_escape_string($_POST['company_code'][$key]); 
    $mycompany[] = "(123,'$name','$code')"; 
} 
$sql = "INSERT INTO `table` (order_num,company_name,company_code) VALUES "; 
$sql .= implode(",",$mycompany); 

Answer 2

INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','DELL','axc89'); 
INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','IBM','bxc90'); 

查询可以使用数组

$arrray_to_be_inserted=array 
(
    [0]=>array('123','DELL','axc89'), 
    [1]=>array('123','IBM','bxc90') 
); 

Answer 3

不是传递价值在的foreach一个新的变量，尝试访问为$键和$值，试试这个，看看它是否能帮助你

<?php 

$company_name = array("DEL","IBM"); 
$company_code = array("1","2"); 
$order_num = array("4","5"); 

if($company_name) 
{ 
foreach($company_name as $key => $value) 
{ 
    $mycompany[] = $value; 
    $mycompanycode[] = $company_code[$key]; 
    $myordernum[] = $order_num[$key]; 
} 
} 

？>

只要确保名字和他们的值相互对应。