MySQL的左与交叉连接的连接查询问题

Question

我有2个表请参见链接和当前正在运行的查询我面临
1.服用太多的时间来执行
2.我想如果 http://sqlfiddle.com/#!9/40d9d/2

问题日期范围内的日期'x'在tbl_appoitmens表中没有任何信息，那么很多结果显示为零，但所有AppointmentTimeID都在tbl_appointmentschedule_details中。
3.我想验证这3个新列AppointmentTypeID,AppointemntStatus和AvailableInMarket从tbl_appointments。
4. ScheduleID从tbl_appointmentschedule_details

查询输出速度确实不管我们可能会选择像2 - 一次3年记录。

结果我想演出是这样的

 
AppointmentTimeID AppointmentDate  NoOfApplicants 
22     2015-10-16    2 
23     2015-10-16    4 
24     2015-10-16    5 
25     2015-10-16    2 
26     2015-10-16    2 
22     2015-10-17    5 
23     2015-10-17    2 
24     2015-10-17    2 
25     2015-10-17    2 
26     2015-10-17    2 
22     2015-10-18    0 
23     2015-10-18    0 
24     2015-10-18    0 
25     2015-10-18    0 
26     2015-10-18    0 

Answer 1

试试这个：

select t4.AppointmentTimeID, t4.AppointmentDate,ifnull(t5.NumberOfApplicants,0) 
from 
    (select distinct t2.AppointmentTimeID, t1.AppointmentDate 
    from tbl_appointmentschedule_details t2 join (select t.AppointmentDate from (
SELECT adddate('2015-10-16', @rownum := @rownum + 1) as 'AppointmentDate' FROM tbl_appointments 
JOIN (SELECT @rownum := -1) r 
LIMIT 31 
) t 
where t.AppointmentDate between '2015-10-16' and '2015-10-18') t1) t4 
left join 
    (SELECT t2.AppointmentTimeID,t1.AppointmentDate,sum(t1.NumberOfApplicants) as 'NumberOfApplicants' 
    FROM tbl_appointmentschedule_details t2 
    LEFT JOIN tbl_appointments t1 on t2.AppointmentTimeID=t1.AppointmentTimeID 
    WHERE t1.AppointmentStatus='Pending' AND t1.AvailableInMarket=0 
    GROUP BY t2.AppointmentTimeID,t1.AppointmentDate) t5 
on t4.AppointmentDate=t5.AppointmentDate and t4.AppointmentTimeID=t5.AppointmentTimeID 
having t4.AppointmentTimeID!=0 
order by t4.AppointmentDate,t4.AppointmentTimeID;