我有以下条件代码,如果具有相应用户名的记录不存在,它将插入新记录,并在记录存在时更新记录。这工作正常。sql更新时不会覆盖现有信息
但是,目前,如果我插入一条新记录,并且只插入名字和姓氏,并且可能地址详细信息中的电话信息被留为空白,这很好。如果我希望只用电话记录更新记录,则名称和地址信息将被替换为无。
我想知道的是,如果它可能有一个简单的方法来填充我的PHP的HTML形式更新信息,与我将更新字段的内容?我使用
<input type="text" name="uniquename" />
为了得到用户输入,然后将其传递给javascript函数,然后将其传递回下面PHP代码。如果这是不可能的,有没有一种简单的方法来工作一些SQL/PHP的魔术,只更新一个字段相应的userinput不是空的?
$usernameQuery = "select username from USERS where username = '" . $con->escape_string($username) . "'";
$xblah = $con->query($usernameQuery);
while ($row = mysqli_fetch_assoc($xblah))
{
$checkUsername = $row['username'];
}
if ($checkUsername == null) {
$userQuery = "INSERT INTO USERS VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
if ($userInfo = $con->prepare($userQuery)) {
$userInfo->bind_param("ssssssssssssssssssss", $username, $firstname, $lastname, $flaggedauctions, $lastauction, $street1, $city1, $postcode1, $street2, $city2, $postcode2, $phone, $mobilephone, $fax, $email, $website, $bank, $banknumber, $accountnumber, $comments);
$userInfo->execute();
$userInfo->close();
echo "true";
} else {
echo "false";
}
print_r($con->error);
}
else if ($checkUsername == $username) {
$userQuery = "UPDATE USERS SET firstname = ?, lastname = ?, flaggedauctions = ?, lastauction = ?, street1 = ?, city1 = ?, postcode1 = ?, street2 = ?, city2 = ?, postcode2 = ?, phone = ?, mobilephone = ?, fax = ?, email = ?, website = ?, bank = ?, banknumber = ?, accoutnumber = ? WHERE username = ?";
if ($userInfo = $con->prepare($userQuery)) {
$userInfo->bind_param("sssssssssssssssssss", $firstname, $lastname, $flaggedauctions, $lastauction, $street1, $city1, $postcode1, $street2, $city2, $postcode2, $phone, $mobilephone, $fax, $email, $website, $bank, $banknumber, $accountnumber, $username);
$userInfo->execute();
$userInfo->close();
echo "true";
} else {
echo "false";
}
print_r($con->error);
}
嗯,谢谢。 bindArgs发生了什么? – 2009-04-16 04:05:10
我的PHP技巧有点生疏,但我认为你可以将$ bindArgs传递给bind_param函数。 我相信你可以将数组传递给PHP中的可变数字参数函数。 – oscarkuo 2009-04-16 04:17:43