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我使用Google脚本将有关Trello卡片的信息导入Google表格。它对我来说工作得很好,但是今天突然所有的卡片都为每一条数据拉入'Undefined'。但我无法弄清楚为什么这个突然停止工作。Google脚本可将Trello数据导入Google表格
的谷歌脚本如下:这个问题我正在寻找此代码
function onOpen() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var menuEntries = [ {name: "Update from Trello", functionName: "main"},];
ss.addMenu("Trello", menuEntries);
}
// trello variables
var api_key = "XXXXX";
var api_token = "XXXXX";
var board_id = "XXXXX";
var url = "https://api.trello.com/1/";
var key_and_token = "key="+api_key+"&token="+api_token;
//called by google docs apps
function main() {
var ss = SpreadsheetApp.getActiveSheet().clear();
ss.appendRow(["Date", "Task", "Who", "List", "Link"]);
var response = UrlFetchApp.fetch(url + "boards/" + board_id + "/lists/all/?" + key_and_token);
var lists = JSON.parse((response.getContentText()));
Logger.log(lists);
for (var i=0; i < lists.length; i++) {
var list = lists[i];
var response = UrlFetchApp.fetch(url + "list/" + list.id + "/cards/all?" + key_and_token);
var cards = JSON.parse(response.getContentText());
if(!cards) continue;
for (var j=0; j < cards.length; j++) {
var card = cards[j];
Logger.log(cards);
var response = UrlFetchApp.fetch(url + "cards/" + card.id + "/actions/?" + key_and_token);
var carddetails = JSON.parse(response.getContentText());
if(!carddetails) continue;
Logger.log(carddetails);
for (var k=0; k < carddetails.length; k++) {
var dato = carddetails[k].date;
var fullname = carddetails[k].memberCreator.fullName;
var name = card.name;
var link = card.url;
var listname = list.name;
Logger.log(name);
Logger.log(dato);
Logger.log(fullname);
Logger.log(link);
Logger.log(listname);
}
ss.appendRow([dato, name, fullname, listname, link]);
}
}
}