2011-04-11 123 views
2

我有以下表格:SQL - 多表连接并选择条件的第一条记录

Projects (ID, Name, ManagerUser_ID) 
Users(ID, Name, Active) 
Delegates(ProjectID, UserID, OrderNo) 

ManagerUser_ID是项目经理的项目,并且是用户表的链接。用户,但是可以是Inactive。因此,Delegates表是定义可以访问项目数据的用户的多对多表。

我需要的是为Active的项目选择第一个代表,假设经理为InactiveOrderNo字段指定代表的顺序(1代表第一位)。

一些样本数据:

Project 
1, Project1, 2 
2, Project2, 4 
3, Project3, 1 

Users 
1, Joe, true 
2, John, false 
3, Dave, true 
4, Bob, false 

Delegates 
1, 4, 1 
1, 1, 2 
1, 3, 3 
2, 2, 1 
2, 4, 2 
2, 3, 3 

所以我查询的输出需要显示:

Project1, Joe 
Project2, Dave 
Project3, Joe 

显示项目和用户对每一个项目,如果ManagerUser_ID是不活动的地方,然后选择User in Delegates最低OrderNoActive

回答

1

这似乎这样的伎俩(使用窗口功能)

SELECT P.Name, ISNULL(U.Name, FirstDelegate.Name) AS ProjManager 
FROM Projects P LEFT OUTER JOIN 
     Users U ON P.ManagerUser_ID = U.ID AND U.Active = 1 LEFT OUTER JOIN 
     (
      SELECT * FROM 
      (
       SELECT D.ProjectID, 
         US.Name, 
         ROW_NUMBER() OVER (PARTITION BY ProjectID ORDER BY OrderNo) AS SeqNo 
       FROM Delegates D INNER JOIN 
         Users US ON D.UserID = US.ID 
       WHERE US.Active = 1 
      ) AS Del 
      WHERE Del.SeqNo = 1 
     ) AS FirstDelegate ON P.ID = FirstDelegate.ProjectID 
0
select p.name, 
u.name, 
min(d.orderNo) 
from projects p, 
users u, 
users manager, 
delegates d 
where p.ManagerUser_ID = manager.id 
and manager.active = false 
and p.id = d.projectId 
and d.userid = u.id 
group by p.name, 
u.name 
+0

不幸的是,这并没有收回项目的第一个活跃代表。这列出了该项目的所有用户以及订单号。需要在某个地方进行调用,将结果集限制为处于活动状态的最低OrderNo。 – Simon 2011-04-11 08:50:24

1

我认为这将是这样的事情。这个想法是做一个额外的连接(使用左连接)来找到一个更早的有效行。如果你能找到这一行,那么很明显你正在构建的当前行不是你想要一个:

select p.Name,m.Name from Projects p inner join Users m on p.ManagerUser_ID = m.ID and m.Active = 1 
union all 
select 
    p.Name, 
    u.Name 
from 
    Projects p 
     inner join 
    Delegates d 
     on 
      p.ID = d.ProjectID 
     inner join 
    Users u 
     on 
      d.UserID = u.ID and 
      u.Active = 1 
     left join 
    Delegates d_anti 
     inner join 
    Users u_anti 
     on 
      d_anti.UserID = u_anti.ID and 
      u_anti.Active = 1 
     on 
      p.ID = d_anti.ProjectID and 
      d_anti.OrderNo < d.OrderNo 
where 
    u_anti.ID is null 
+0

这看起来非常接近,生病必须明天检查。但是,最后的ON子句不正确 - u_anti.OrderNo Simon 2011-04-11 10:03:34

+0

@Simon - 是的,你会在那里正确的。 – 2011-04-11 11:41:56

1
Select projectName, userName 
From 

(
    Select projectName, userName, row_number() over (partition by projectName order by priority ASC) as rank 
    From 
    (
     SELECT p.name as projectName, u.name as userName, 1 as priority 
     FROM projects p INNER JOIN users u ON u.active = true and u.id = p.ManagerUser_ID 

     UNION 

     SELECT TOP(1) p.name, u.name, 2 
     FROM Delegates d INNER JOIN projects p ON p.id = d.projectId 
         INNER JOIN users u ON u.id = d.userId 
     Where u.active = true 
     Order by u.OrderNo ASC 
    ) 
) 
where rank = 1