2012-12-14 68 views
0

我有一个PHP函数来做模糊时间(也就是前一段时间)。将PHP模糊时间转换为Javascript?

这是从服务器端建立表时使用,但现在我们通过JavaScript向表中添加新项目,我们有能力选择日期,因此我需要在Javascript中复制功能,但有它接受格式为YYYY-MM-DD的日期,例如2012-12-14

我将开始研究它,但是我在JavaScript中使用日期很糟糕,所以在这里发布它让一个人可以更快地做到这一点。

功能如下:

/** 
* Convert date into a 'fuzzy' format 
* - 15 minutes ago, 3 days ago, etc. 
* Pass a unix timestamp or a string to parse to a date. 
* @param string|number 
* @return string 
*/ 
function fuzzyTime($date_from, $invalid_date = 'a long time ago') { 

    $_time_formats = array(
     array(60, 'just now'), 
     array(90, '1 minute'), 
     array(3600, 'minutes', 60), 
     array(5400, '1 hour'), 
     array(86400, 'hours', 3600), 
     array(129600, '1 day'), 
     array(604800, 'days', 86400), 
     array(907200, '1 week'), 
     array(2628000, 'weeks', 604800), 
     array(3942000, '1 month'), 
     array(31536000, 'months', 2628000), 
     array(47304000, '1 year'), 
     array(3153600000, 'years', 31536000), 
    ); 

    $now = time(); // current unix timestamp 

    // if a number is passed assume it is a unix time stamp 
    // if string is passed try and parse it to unix time stamp 
    if (is_numeric($date_from)) { 
     $dateFrom = $date_from; 
    } elseif (is_string($date_from)) { 
     $dateFrom = strtotime($date_from); 
    } 

    $difference = $now - $dateFrom; // difference between now and the passed time. 
    $val = ''; // value to return 

    if ($dateFrom <= 0) { 
     $val = $invalid_date; 
    } else { 
     //loop through each format measurement in array 
     foreach ($_time_formats as $format) { 
      // if the difference from now and passed time is less than first option in format measurment 
      if ($difference < $format[0]) { 
       //if the format array item has no calculation value 
       if (count($format) == 2) { 
        $val = $format[1] . ($format[0] === 60 ? '' : ' ago'); 
        break; 
       } else { 
        // divide difference by format item value to get number of units 
        $val = ceil($difference/$format[2]) . ' ' . $format[1] . ' ago'; 
        break; 
       } 
      } 
     } 
    } 
    return $val; 
} 

这是我迄今为止,但它返回83年前

var date = '2012-11-14'; 

console.log(fuzzyTime(date)); 

function fuzzyTime($date_from, $invalid_date) { 

    if($invalid_date === undefined){ 
     $invalid_date = 'a long time ago'; 
    } 

    var $_time_formats = [ 
     [60, 'just now'], 
     [90, '1 minute'], 
     [3600, 'minutes', 60], 
     [5400, '1 hour'], 
     [86400, 'hours', 3600], 
     [129600, '1 day'], 
     [604800, 'days', 86400], 
     [907200, '1 week'], 
     [2628000, 'weeks', 604800], 
     [3942000, '1 month'], 
     [31536000, 'months', 2628000], 
     [47304000, '1 year'], 
     [3153600000, 'years', 31536000] 
    ]; 

    var $now = new Date(); // current unix timestamp 
    var $dateFrom = new Date($date_from); 

    var $difference = Math.abs(new Date() - $dateFrom); 

    var $val = ''; // value to return 

    if ($dateFrom <= 0) { 
     $val = $invalid_date; 
    } else { 
     for (var i = 0; i < $_time_formats.length; i++) { 
      var $format = $_time_formats[i]; 

      if ($difference < $format[0]) { 
       //if the format array item has no calculation value 
       if ($format.length == 2) { 
        $val = $format[1] + ($format[0] === 60 ? '' : ' ago'); 
        break; 
       } else { 
        // divide difference by format item value to get number of units 
        $val = Math.ceil($difference/$format[2]) + ' ' + $format[1] + ' ago'; 
        break; 
       } 
      } 
     } 

    } 
    return $val; 
} 

回答

0

嗯知道了,

var date = '2012-12-14 17:52:00'; 

console.log(fuzzyTime(date)); 

function fuzzyTime(date_from, invalid_date) { 

    if (invalid_date === undefined) { 
     invalid_date = 'a long time ago'; 
    } 

    var time_formats = [ 
     [60, 'just now'], 
     [90, '1 minute'], 
     [3600, 'minutes', 60], 
     [5400, '1 hour'], 
     [86400, 'hours', 3600], 
     [129600, '1 day'], 
     [604800, 'days', 86400], 
     [907200, '1 week'], 
     [2628000, 'weeks', 604800], 
     [3942000, '1 month'], 
     [31536000, 'months', 2628000], 
     [47304000, '1 year'], 
     [3153600000, 'years', 31536000] 
    ]; 

    var now = new Date().getTime(); // current unix timestamp 
    var dateFrom = new Date(date_from.replace('-','/')).getTime(); 

    var difference = Math.abs(now - dateFrom)/1000; 

    var val = ''; // value to return 

    if (dateFrom <= 0) { 
     val = invalid_date; 
    } else { 
     for (var i = 0; i < time_formats.length; i++) { 
      var format = time_formats[i]; 

      if (difference < format[0]) { 
       //if the format array item has no calculation value 
       if (format.length == 2) { 
        val = format[1] + (format[0] === 60 ? '' : ' ago'); 
        break; 
       } else { 
        // divide difference by format item value to get number of units 
        val = Math.ceil(difference/format[2]) + ' ' + format[1] + ' ago'; 
        break; 
       } 
      } 
     } 

    } 
    return val; 
}