2014-10-17 100 views
0

我想在我的网页上显示学生信息和学生图像,同时从下拉列表中选择学生ID。下面给出的代码用于显示信息和图像。但图像显示不正确。请检查代码和输出屏幕。很热来显示二进制图像从数据库到图像框。?8

代码:

protected void DropDownList1_SelectedIndexChanged(object sender, EventArgs e) 
{ 

     DataSet1TableAdapters.TextBoxTableTableAdapter tx; 
     tx = new DataSet1TableAdapters.TextBoxTableTableAdapter(); 
     DataTable dt = new DataTable(); 
     dt = tx.GetstudData(int.Parse(DropDownList1.SelectedValue)); 

     foreach (DataRow row in dt.Rows) 
     { 
      TextBox1.Text = (row["FirstName"].ToString()); 
      TextBox2.Text = (row["SecondName"].ToString()); 
      byte[] barrImg = (byte[])row["StudImage"]; 
      string base6=Convert.ToBase64String(barrImg); 
      Image1.ImageUrl = "data:image/jpeg;base6," + base6; 
     } 
} 

SQL查询:

SELECT FirstName, SecondName, StudentImage FROM TextBoxTable WHERE (Id = @Id) 

.aspx的来源:

<div> 
<asp:DropDownList ID="DropDownList1" runat="server" AutoPostBack="True"> 
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> 
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox> 
<asp:Image ID="Image1" runat="server" /> 
</div> 

数据的基础上:

enter image description here

输出:

enter image description here

回答

1

BASE64代替base6 ???

Image1.ImageUrl = "data:image/jpeg;base64," + base6; 
+0

非常感谢。不,它工作完美 – Vipin 2014-10-17 08:47:21