多个IN语句。这会返回良好的数据吗？

Question

SELECT ['VISA CK - 021810$'].[ACCT NBR  #1], ['VISA CK - 021810$'].[ALT CUST NM #1], ['VISA CK - 021810$'].[LAST USED] 
FROM ['VISA CK - 021810$'] 
WHERE ['VISA CK - 021810$'].[ALT CUST NM #1] 
    IN (
     SELECT ['VISA CK - 021810$'].[ALT CUST NM #1] 
     FROM ['VISA CK - 021810$'] 
     GROUP BY ['VISA CK - 021810$'].[ALT CUST NM #1] 
      HAVING COUNT(['VISA CK - 021810$'].[ALT CUST NM #1]) > 1 
     ) 
    AND ['VISA CK - 021810$'].[ACCT NBR  #1] 
    IN (
     SELECT ['VISA CK - 021810$'].[ACCT NBR  #1] 
     FROM ['VISA CK - 021810$'] 
     GROUP BY ['VISA CK - 021810$'].[ACCT NBR  #1] 
      HAVING COUNT(['VISA CK - 021810$'].[ACCT NBR  #1]) > 1 
     ) 

Answer 1

使用改写联接：

SELECT t.[ACCT NBR  #1], 
     t.[ALT CUST NM #1], 
     t.[LAST USED] 
    FROM ['VISA CK - 021810$'] t 
    JOIN (SELECT ['VISA CK - 021810$'].[ALT CUST NM #1] 
      FROM ['VISA CK - 021810$'] 
     GROUP BY ['VISA CK - 021810$'].[ALT CUST NM #1] 
     HAVING COUNT(['VISA CK - 021810$'].[ALT CUST NM #1]) > 1) x ON x.[ALT CUST NM #1] = t.[ALT CUST NM #1] 
    JOIN (SELECT ['VISA CK - 021810$'].[ACCT NBR  #1] 
      FROM ['VISA CK - 021810$'] 
     GROUP BY ['VISA CK - 021810$'].[ACCT NBR  #1] 
     HAVING COUNT(['VISA CK - 021810$'].[ACCT NBR  #1]) > 1) y ON y.[ACCT NBR  #1] = t.[ACCT NBR  #1] 

确保它返回你所期望的数据 - 后调。假设你提供的查询是正确的，JOIN通常比子查询更受欢迎，但审查和比较执行计划会告诉你什么是最适合你的情况。

Answer 2

这是一个有效的SQL结构，但我们无法评论它是否有效。

你的意思是：在['VISA CK - 021810$']每一行，返回该行，如果我找到他们相对都[ACCT NBR #1]和[ALT CUST NM #1] IN子句

Answer 3

是的，它会返回良好的数据匹配。 WHERE子句将确保在使用AND时返回任何数据之前，两个IN子句都受到尊重。