2016-08-03 62 views
0

我有一个关于在jqGrid中使用下拉列表的问题。在我的环境中,我正在使用许可证jqGrid 4.4.4 - 带有MVC 5的jQuery Grid(版本4.4.4)。动态列和在jqGrid中使用下拉列表

在我的代码中,我从我的控制器动态创建ColNamesColModel。除了我希望显示下拉列的值的列之外,一切正常。现在,下拉列表是空的。为什么它是空的?

另外,值应该如何{value:{'FE':'FedEx';'IN':'InTime';'TN':'TNT';'AR':'ARAMEX'}},从控制器中的方法动态加载?

model.CreateMeeting = false; 
SecondOpinionFacade = new SecondOpinionFacade(); 
var meeting = SecondOpinionFacade.GetMeeting(id); 
model.MeetingDay = meeting.StartDate.Date; 
model.MeetingdID = meeting.SecondOpinionMeetingId; 
model.FromTime = meeting.StartDate.ToString("HH:mm"); 
model.ToTime = meeting.EndDate.ToString("HH:mm"); 
model.NrofGroups = meeting.SecondOpinionGroup.Count; 

var list = new[] { new { name = "SecondOpionUserId", index = "SecondOpionUserId", sorttype = "string", sortable=false, hidden = true, editable = true, edittype = "", editoptions= "", formatter = ""} }.ToList(); 

这里我试图把数据放到下拉列表中,但它似乎不工作,因为下拉列表显示为空。

list.Add(new { name = "Deltagare", index = "Deltagare", sorttype = "string", sortable = true, hidden = false, editable = true, edittype = "select", editoptions = "{value:{'FE':'FedEx';'IN':'InTime';'TN':'TNT';'AR':'ARAMEX'}}", formatter = "select" }); 
int counter = 1; 
meeting.SecondOpinionGroup.OrderBy(x=> x.SecondOpinionGroupId).ForEach(x => 
{ 
    list.Add(new {name = x.SecondOpinionGroupId.ToString(), index = "Grupp" + counter, sorttype = "string", sortable = false, hidden = false, editable = true, edittype = "checkbox", editoptions = "{ value: 'True:False' }", formatter = "checkbox" }); 
    counter++; 
}); 

var list2 = new[] { "SecondOpionUserId" }.ToList(); 
list2.Add("Deltagare"); 
for (int i = 1; i <=model.NrofGroups; i++) 
{ 
    list2.Add("Grupp"+i); 
} 

model.ColNames = JsonConvert.SerializeObject(list2); 
model.ColModel = JsonConvert.SerializeObject(list); 
return View(model); 

回答

1

您使用作为editoption值。这是不对的。 editoptions的值应该是对象。尝试更换

editoptions = "{ value: 'True:False' }" 

editoptions = "{value:{'FE':'FedEx';'IN':'InTime';'TN':'TNT';'AR':'ARAMEX'}}" 

editoptions = new { value = "True:False" } 

editoptions = new { value = "FE:FedEx;IN:InTime;TN:TNT;AR:ARAMEX" } 
+0

谢谢!这解决了这个问题,当我将editoptions从一个字符串改为一个对象时,出现了一个小问题。我必须将列表中的所有其他editoptions设置为对象,否则我会遇到compiliation错误。但我只是将它们设置为editoptions = new {value =“”} – user3197410