sys.types 系统对象 syscolumns中 的sysindexes INFORMATION_SCHEMA.COLUMNS
能否也帮我这个转换为与Oracle语法
DECLARE @tableUpdateCount tinyint
set @tableUpdateCount = 0
/*
* CALCDETL.ALIAS - 1
*/
if exists (select * from syscolumns where id = (select id from sysobjects where name = 'ABC' and type = 'U') and name = 'ALIAS' and xusertype = (select user_type_id from sys.types where name = 'nvarchar') and prec = 20)
begin
set @tableUpdateCount = @tableUpdateCount + 1
print ' '
print '1. ABC.ALIAS exists'
end
是否有任何工具可以轻松地转换sql-to-oracle语法?
谢谢!
可以请你点我正确的下载链接Oracle的SQL Developer移植工作台?当我点击上面的链接时,它会将我重定向到主页。谢谢 – FerdzBM 2011-03-14 12:06:40