多加入同一个表，甲骨文

enter image description here 多加入同一个表，甲骨文

我想下面的查询

SELECT Customer.*, 
     ElectrnicItem.Product1 AS ElectronicItem1, 
     ElectrnicItem.Product2 AS ElectronicItem2, 
     ElectrnicItem.Product3 AS ElectronicItem3, 
     ApparelItem.Product1 AS ApparelItem1, 
     ApparelItem.Product2 AS ApparelItem2, 
     ApparelItem.Product3 AS ApparelItem3 
FROM Customer 
LEFT JOIN Inventory AS ElectrnicItem 
ON (Customer.CustomerID = ElectrnicItem.CustomerID) 
LEFT JOIN Inventory AS ApparelItem 
ON (Customer.CustomerID = ApparelItem.CustomerID)

但它总是返回：含糊不清的

ORA-00918列

来源

2013-05-03 BreakHead

您是否可以将Customer. *分解为Customer.CustomerID，Customer.CustomerName？不知道这是否是问题。 – Hazaart 2013-05-03 09:09:19

客户表中的列名称是什么？ – Nagasaki 2013-05-03 09:10:52

你可以用'CREATE TABLE'语句替换图像吗？发布实际代码（我们可以复制和粘贴以测试自己的文本）通常比代码图片更好。 – 2013-05-03 09:12:37

您错过了任何谓词来标识清单中的行为'Elec tronic“或”服装“。不知道这是修复。

来源

2013-05-03 09:07:39

这个怎么样？

SELECT a.customer_id, a.customer_name, b.product1 electronicitem1, 
     b.product2 electronicitem2, b.product3 electronicitem3, 
     c.product1 apparelitem1, c.product2 apparelitem2, 
     c.product3 apparelitem3 
FROM customer a, inventory b, inventory c 
WHERE a.customer_id = b.customer_id(+) 
    AND b.product_type(+) = 'Electronic' 
    AND a.customer_id = c.customer_id(+) 
    AND c.product_type(+) = 'Apparel';

来源

2013-05-03 09:40:05 Noel

我创建了表Customer和Inventory，还插入了您提供的值。以下是查询：

select customer.*,ElectrnicItem.Product1 as ElectronicItem1, 
ElectrnicItem.Product2 as ElectronicItem2, 
ElectrnicItem.Product3 as ElectronicItem3, 
ApparelItem.Product1 as ApparelItem1, 
ApparelItem.Product2 as ApparelItem2, 
ApparelItem.Product3 as ApparelItem3 
from customer 
left join inventory as ElectrnicItem on 
(customer.CustomerID = ElectrnicItem.CustomerID) 
left join inventory as ApparelItem 
on (customer.CustomerID = ApparelItem.CustomerID)

它工作正常，并给出以下结果：

1 David Miller mobile headphone trimmer mobile headphone trimmer 
    2 Johnson   jeans tshirt  NULL jeans tshirt  NULL    
    3 Diggs   NULL NULL  NULL NULL NULL  NULL

你提到的预计产量将永远无法实现。由于Customer表包含CustomerId和CustomerName,Customer.*将检索CustomerId和CustomerName。因此CustomerName列不能包含任何NULL 值。

来源

2013-05-03 09:57:27 Joshi

好吧，有点晚了，但是... 您不能使用AS来为Oracle中的表格别名，只能为列别名。尝试从表别名中删除所有这些AS：

SELECT Customer.*, 
     ElectrnicItem.Product1 AS ElectronicItem1, 
     ElectrnicItem.Product2 AS ElectronicItem2, 
     ElectrnicItem.Product3 AS ElectronicItem3, 
     ApparelItem.Product1 AS ApparelItem1, 
     ApparelItem.Product2 AS ApparelItem2, 
     ApparelItem.Product3 AS ApparelItem3 
FROM Customer 
LEFT JOIN Inventory ElectrnicItem 
ON (Customer.CustomerID = ElectrnicItem.CustomerID) 
LEFT JOIN Inventory ApparelItem 
ON (Customer.CustomerID = ApparelItem.CustomerID)

来源

2016-09-30 07:26:09 Rodrigo

多加入同一个表，甲骨文

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