所以即时建立一个基于pi的机器人。 它使用ps3控制器进行输入。当按下X按钮时,它会拍摄照片。出于某种原因,一次只需要5次左右的拍摄。有没有办法反弹输入,以便只识别一次按键?python pygame如何去除按钮?
我假设它的注册多个印刷机每次...部分代码连接,但我必须说明大部分是从piborg.org使用
joystick = pygame.joystick.Joystick(0)
button_take_picture = 14 # X button
while running:
# Get the latest events from the system
hadEvent = False
events = pygame.event.get()
# Handle each event individually
for event in events:
if event.type == pygame.QUIT:
# User exit
running = False
elif event.type == pygame.JOYBUTTONDOWN:
# A button on the joystick just got pushed down
hadEvent = True
elif event.type == pygame.JOYAXISMOTION:
# A joystick has been moved
hadEvent = True
if hadEvent:
if joystick.get_button(button_take_picture):
take_picture()
你可以阻止一个以上的调用'take_picture()'直到你得到一个'JOYBUTTONUP' – Tomer
有意思,你能解释更多吗?即时通讯全新的pygame /使用按钮和即时通讯相当新的python ...这是我的第一个大项目!你会简单地'如果event.type == pygame.JOYBUTTONUP:'在'take_picture()'之前? – JONAS402
是的,只有释放按钮时,才会拍照。 – Tomer