矩形重叠，但说它在里面？

Question

我做了一个程序，用户用CenterX和CenterY坐标，宽度和高度创建两个自定义矩形。用户指定这些尺寸后，程序将显示一个矩形是否包含另一个矩形，与另一个矩形重叠，还是完全不符合。这里是我的代码：

import javafx.application.Application; 
import javafx.scene.Scene; 
import javafx.stage.Stage; 
import javafx.scene.shape.*; 
import javafx.scene.text.*; 
import javafx.scene.paint.Color; 
import javafx.scene.layout.Pane; 
import java.util.*; 

public class TwoRectangles extends Application 
{ 
    public void start(Stage stage) 
    { 
     Pane pane = new Pane(); 

     Scanner input = new Scanner(System.in); 
     System.out.print("Enter the X and Y center coordinates for rectangle1: "); 
     double xCord1 = input.nextDouble(); 
     double yCord1 = input.nextDouble(); 

     System.out.print("Enter the Width and Height for rectangle1: "); 
     double width1 = input.nextDouble(); 
     double height1 = input.nextDouble(); 

     System.out.print("Enter the X and Y center coordinates for rectangle2: "); 
     double xCord2 = input.nextDouble(); 
     double yCord2 = input.nextDouble(); 

     System.out.print("Enter the Width and Height for rectangle2: "); 
     double width2 = input.nextDouble(); 
     double height2 = input.nextDouble(); 

     Rectangle rectangle1 = new Rectangle(xCord1, yCord1, width1, height1); 
     Rectangle rectangle2 = new Rectangle(xCord2, yCord2, width2, height2); 

     rectangle1.setFill(null); 
     rectangle2.setFill(null); 
     rectangle1.setStroke(Color.BLACK); 
     rectangle2.setStroke(Color.BLACK); 

    // Compute the 4 corners's coordinates for the rectangle 
     double r1x1 = xCord1 - (width1/2.0); 
     double r1x2 = xCord1 + (width1/2.0); 
     double r1y1 = yCord1 + (height1/2.0); 
     double r1y2 = yCord1 - (height1/2.0); 

     double r2x1 = xCord2 - (width2/2.0); 
     double r2x2 = xCord2 + (width2/2.0); 
     double r2y1 = yCord2 + (height2/2.0); 
     double r2y2 = yCord2 - (height2/2.0); 


    if ((r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2)) 
     { 
     Text containText = new Text(500, 500, "One rectangle is contained in another"); 
     pane.getChildren().add(containText); 
     } 

    else if ((r1x1 < r2x2) && (r1x2 > r2x1) && (r1y1 < r2y2) && (r1y2 > r2y1)) 
     { 
      Text overlapText = new Text(500, 500, "The rectangles overlap"); 
      pane.getChildren().add(overlapText); 

     } 

     else 
     { 
      Text noneText = new Text(500, 500, "The rectangles do not overlap"); 
      pane.getChildren().add(noneText); 
     }  
     pane.getChildren().addAll(rectangle1, rectangle2); 
     Scene scene = new Scene(pane); 
     stage.setTitle("Overlapping Rectangles"); 
     stage.setScene(scene); 
     stage.show(); 
    } 
} 

每当我进入，（50，50）的centerX和centerY坐标两个矩形，宽度：20，为rectangle1高度50和宽度50，为rectangle2高度20它告诉我矩形在彼此内部而不是彼此重叠。我究竟做错了什么？

Answer 1

你的问题是Y坐标。第二个比第一个小。这意味着测试将变得不太可读，例如

(r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2) 

变为（与也检查，如果R 2是在R1）：

(r1x1 >= r2x1 && r1x2 <= r2x2 && r1y1 <= r2y1 && r1y2 >= r2y2) || 
//         ^^    ^^ 
(r2x1 >= r1x1 && r2x2 <= r1x2 && r2y1 <= r1y1 && r2y1 >= r1y2)